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inessss [21]
4 years ago
14

If the speed of an object is doubled, its kinetic energy will

Physics
2 answers:
otez555 [7]4 years ago
7 0
3. remain the same would be the asnwer
Kamila [148]4 years ago
7 0
I would say 1 or 3
I think this website would help you : )
https://quizlet.com/143048348/year-10-physics-forces-motion-and-energy-flash-cards/

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Seeing light coming out from a crack in the wall is what type of wave interaction?
Norma-Jean [14]

Answer:

C

becuase its where a wave (light etc) goes through a narrow area or across an edge of an area

3 0
3 years ago
Algunos estudiantes de tu promoción consideran que se debería aumentar el número de horas semanales de Educación Física. Otros c
Pavlova-9 [17]

La respuesta correcta para esta pregunta abierta es la siguiente.

Te compartimos las tres ideas que te pueden ayudar para hacer tu artículo.

Título:

La Educación Física, una prioridad para las escuelas.

Existe una frase milenaria que se le atribuye a los griegos que dice "Mente sana en cuerpo sano."

Y es muy cierta.

Las escuelas deberían considerar seriamente aumentar el número de horas semanales para la impartición de la educación física por las siguientes razones.

1.- La educación física es vital para el desarrollo físico del estudiante. Desde los grados más básicos, las escuelas deberían fortalecer la enseñanza de la educación física por motivos de salud, y dejar este buen hábito en los alumnos para toda la vida.

2.- La educación física, mejora el rendimiento académico ya que ayuda oxigenando los músculos, fortaleciendo el cerebro para que pueda concentrase mejor, despeja a los alumnos de tal forma que puedan regresar a los salones e clase más "despiertos."

3.- La educación física sirve para introducir la importancia de practicar deporte toda la vida, y hacerlo en la etapa escolar a través de equipos deportivos como el Futbol Americano, el beisbol, el basquetbol, el volibol, el soccer, y otros tantos.

Este idea del trabajo en equipo a través del deporte es muy importante para desarrollar habilidades como el liderazgo, el compromiso, la constancia y el superar la adversidad.

El profesor de educación física debe enseñarte la forma correcta de respirar cuando haces ejercicio, la importancia de la relajación del cuerpo para iniciar una actividad. El profesor debe hacer énfasis en la etapa del calentamiento y el estiramiento para preparar al cuerpo antes de realizar el ejercicio. Así como muchas otras enseñanzas.

Por esa razón, las escuelas deberían considerar seriamente la posibilidad de aumentar las horas de educación física por semana.

4 0
3 years ago
Lolz plz help me with this it’s due soon
White raven [17]

Answer:

Explanation:

c slowing down since the distance is going down and the time is moving up.

7 0
3 years ago
You drop a 30 g pebble down a well. You hear a splash 2.7 s later. What was the pebble’s speed just as it reaches the water? Ass
Flauer [41]

vf=vi+at

No need for rearranging because it is already set up for Vf (final velocity)

a= -9.8m/s² (because it is falling)

vi= 0

t= 2.7

0 + -9.8(2.7) = vf

vf = -26.5 (-26.46)

7 0
3 years ago
Figure 8-56 shows a solid, uniform cylinder of mass 7.00 kg and radius 0.450 m with a light string wrapped around it. A 3.00-N t
AVprozaik [17]

Answer:

a) The cylinder has an angular acceleration of 3.810 radians per square second, b) The frictional force has a magnitude of 9 newtons and has the same direction of tension force.

Explanation:

The external force exerted on string creates a tension force that tries to move the cylinder in translation, but it is opposed by the friction force between cylinder and ground that generates rolling on cylinder. The Free Body Motion on cylinder-string system is presented below as attachment. Given that cylinder is a rigid body in planar motion, two equations of equilibrium for translation and an equation of equilibrium for rotation are needed to represent the system, which are now described:

\Sigma F_{x} = T + f = M\cdot R\cdot \alpha

\Sigma F_{y} = N - M\cdot g = 0

\Sigma M_{G} = (T-f)\cdot R = I_{G}\cdot \alpha

Where:

T - Tension, measured in newtons.

f - Friction force, measured in newtons.

M - Mass of the cylinder, measured in kilograms.

R - Radius of the cylinder, measured in meters.

\alpha - Angular acceleration, measured in radians per square second.

N - Normal force from ground exerted on cylinder, measured in newtons.

g - Gravitational acceleration, measured in meters per square second.

I_{G} - Moment of inertia of the cylinder with respect to its center of mass, measured in kilogram-square meters.

The moment of inertia of the cylinder is:

I_{G} = \frac{1}{2}\cdot M\cdot R^{2}

a) The angular acceleration is determined by solving on first and third equation after eliminating  friction force:

f = M\cdot R \cdot \alpha - T

(T-M\cdot R\cdot \alpha+T) \cdot R = I_{G}\cdot \alpha

2\cdot T\cdot R = (I_{G} + M\cdot R^{2})\cdot \alpha

\alpha = \frac{2\cdot T\cdot R}{I_{G}+M\cdot R^{2}}

\alpha = \frac{2\cdot T \cdot R}{\frac{1}{2}\cdot M\cdot R^{2}+M\cdot R^{2} }

\alpha = \frac{4\cdot T}{3\cdot M\cdot R}

If T = 3\,N, M = 7\,kg and R = 0.45\,m, then:

\alpha = \frac{4\cdot (3\,N)}{(7\,kg)\cdot (0.45\,m)}

\alpha = 3.810\,\frac{rad}{s^{2}}

The cylinder has an angular acceleration of 3.810 radians per square second.

b) The magnitude of the frictional force can be determined with the help of the following expression:

f = M\cdot R \cdot \alpha - T

Given that T = 3\,N, M = 7\,kg, R = 0.45\,m and \alpha = 3.810\,\frac{rad}{s^{2}}, the magnitude of the friction force is:

f = (7\,kg)\cdot (0.45\,m)\cdot \left(3.810\,\frac{rad}{s^{2}} \right)-3\,N

f = 9\,N

The frictional force has a magnitude of 9 newtons and has the same direction of tension force.

5 0
4 years ago
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