We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

Where,
- F is force
- m is mass
- a is acceleration
In our case,
- F = ?
- m = 2500 kg
- a = 20m/s

<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>
the awnser to ur question is D
Answer:
a) 2.41 km
b) 38.8°
Questions c and d are illegible.
Explanation:
We can express the displacements as vectors with origin on the point he started (0, 0).
When he traveled south he moved to (-3, 0).
When he moved east he moved to (-3, x)
The magnitude of the total displacement is found with Pythagoras theorem:
d^2 = dx^2 + dy^2
Rearranging:
dy^2 = d^2 - dx^2


The angle of the displacement vector is:
cos(a) = dx/d
a = arccos(dx/d)
a = arccos(3/3.85) = 38.8°
Answer:
Both
Explanation:
The lithosphere is part of both the crust and the mantle.
It is the surface layer of the earth and also the most rigid layer. It is formed by the crust and the outermost part of the mantle. It is divided into two types: continental lithosphere and oceanic lithosphere.
The oceanic lithosphere has an approximate thickness of 50 - 100km, and the continental olithosphere of 40 - 200km.
Answer:
Yes, there a link between number of bulbs and current drawn from the power pack.
Explanation:
In an Electrical circuit, we have resistors present in that circuit. These resistors can be connected in two ways.
a) Series connection
b) Parallel connection
There is a link or a relationship between number of bulbs and the current drawn from the power pack. This is because the number of bulbs is equivalent to or equal to the number of resistors.
Hence,
a) In a series connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) decreases.
b) In a parallel connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) increases.