Answer:
The buoyant force is 3778.8 N in upward.
Explanation:
Given that,
Mass of balloon = 222 Kg
Volume = 328 m³
Density of air = 1.20 kg/m³
Density of helium = 0.179 kg/m³
We need to calculate the buoyant force acting
Using formula of buoyant force
![F_{b}=\rho_{air}\times V_{b}\times g](https://tex.z-dn.net/?f=F_%7Bb%7D%3D%5Crho_%7Bair%7D%5Ctimes%20V_%7Bb%7D%5Ctimes%20g)
Where,
= density of air
V = Volume of balloon
g = acceleration due to gravity
Put the value into the formula
![F_{b}=1.20\times321\times9.81](https://tex.z-dn.net/?f=F_%7Bb%7D%3D1.20%5Ctimes321%5Ctimes9.81)
![F_{b}=3778.8\ N](https://tex.z-dn.net/?f=F_%7Bb%7D%3D3778.8%5C%20N)
This buoyant force is in upward direction.
Hence, The buoyant force is 3778.8 N in upward.
The trains take <u>57.4 s</u> to pass each other.
Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.
therefore,
![v_A=90 km/h\\ v_B=-80 km/h](https://tex.z-dn.net/?f=v_A%3D90%20km%2Fh%5C%5C%20v_B%3D-80%20km%2Fh)
The relative velocity of the train A with respect to B is given by,
![v_A_B=v_A-v_B\\ =(90km/h)-(-80km/h)\\ =170km/h](https://tex.z-dn.net/?f=v_A_B%3Dv_A-v_B%5C%5C%20%3D%2890km%2Fh%29-%28-80km%2Fh%29%5C%5C%20%3D170km%2Fh)
If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.
The trains are a distance d = 2.71 km apart.
Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,
![t= \frac{d}{v_A_B}](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7Bd%7D%7Bv_A_B%7D)
Substitute 2.71 km for d and 170 km/h for ![v_A_B](https://tex.z-dn.net/?f=v_A_B)
![t= \frac{d}{v_A_B}\\ =\frac{2.71 km}{170 km/h} \\ =0.01594 h](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7Bd%7D%7Bv_A_B%7D%5C%5C%20%3D%5Cfrac%7B2.71%20km%7D%7B170%20km%2Fh%7D%20%5C%5C%20%3D0.01594%20h)
Express the time in seconds.
![t=(0.01594h)(3600s/h)=57.39s](https://tex.z-dn.net/?f=t%3D%280.01594h%29%283600s%2Fh%29%3D57.39s)
Thus, the trains cross each other in <u>57.4 s</u>.
Answer:
The achievement of lifting a rocket off the ground and into space can be explained by Newton's third law of motion. What is required for a rocket to lift off into space? Thrust is required for a rocket to lift off into space, ... An object that travels around another object in space is called a satellite.
Explanation:
Answer:
Given:
m=1000kg
u= 16.7m/s
v=0m/s
F=8000N
Required:
s=?
Solution:
F=m × a
8000N=1000kg × a
a=8m/s^2
Since it decelerate a= -8m/s^2
v^2 = u^2 + 2as
s=v^2 - u^2 / 2a
s= 0 - (16.7m/s)^2 / 2 × -8m/s^2
s= -278.89/-16
s= 17.43m
The car travels approximately 17.43m before it stops
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