Mass percentage is defined as the ratio of mass of the element to the total mass of the compound.
The formula of mass percentage is given by:
Mass percentage = (1)
mass of nitrogen = 56.00 grams
Let x be the total mass of the compound.
Put the given values in formula (1):
x=
x= 151.92 g
total mass of the compound = 151.92 g
To calculate the mass of oxygen in grams, subtract the mass of nitrogen from the total mass of the compound.
Mass of oxygen = 151.92 g - 56 .00 g = 95.92 g
Thus, mass of oxygen in grams = 95.92 grams.
<u>Answer:</u>
Carbon (i) : quaternary carbon
Carbon (ii) : secondary carbon
Carbon (iii) : tertiary carbon
Carbon (iv) : secondary carbon
<u>Explanation:</u>
Carbons can be classified into 4 categories:
(1) Primary carbon : These are the atoms where the carbon atom is attached to one other carbon atom.
(2) Secondary carbon : These are the atoms where the carbon atom is attached to two other carbon atoms.
(3) Tertiary carbon : These are the atoms where the carbon atom is attached to three other carbon atoms.
(4) Quaternary carbon : These are the atoms where the carbon atom is attached to four other carbon atoms.
In the given structure:
Carbon (i) is attached to 4 further carbon atoms and hence, it is a quaternary carbon.
Carbon (ii) is attached to 2 further carbon atoms and hence, it is a secondary carbon.
Carbon (iii) is attached to 3 further carbon atoms and hence, it is a tertiary carbon.
Carbon (iv) is attached to 2 further carbon atoms and hence, it is a secondary carbon.
Answer:
see explanation below
Explanation:
First, you are not providing any data of the bromide solution to calculate the mass. So, in order to help you, I will take some random values from a similar exercise, so you can solve this later with your data.
Let's suppose you add 360 mL of a 1.45 mol/L of a calcium bromide solution into the flask. To calculate the mass it was added, you need to calculate first the moles added. This can be done with the following expression:
M = n/V
Where:
M: molarity of solution
n: moles of solution
V: volume (in liters) of solution
here, you have to solve for n, so:
n = M*V
replacing the above data you have:
n = 1.45 * (0.360) = 0.522 moles
Now that we have the moles, you can calculate the mass by the following expression:
m = n * MM
Where MM it's the molar mass of calcium bromide. The reported MM of calcium bromide is 199.89 g/mol, so replacing:
m = 199.89 * 0.522
m = 104.34 g
And this is the mass that was added of the solution. As I stated before, use your data in this procedure, and you should get an accurate result.
Answer:
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