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scoundrel [369]

2 years ago

13

Which molecule is pentanoic acid?

1 answer:

Lana71 [14]2 years ago

7 0

Answer:

A

Explanation:carboxyli

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In a 4.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.10 atm, how many moles of steam

Olenka [21]

Answer: 0.39mol of the steam are in the cooker.

Explanation:Please see attachment for explanation

7 0

3 years ago

Tracy observes an organism that lives in a lake by her house. The organism has an internal skeleton, scales, fins, and gills. Th

andrey2020 [161]

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2 years ago

Read 2 more answers

What exacerbates the heat waves?

KIM [24]

Answer:

A heatwave occurs when a system of high atmospheric pressure moves into an area and lasts two or more days.

Explanation:

In such a high-pressure system, air from upper levels of our atmosphere is pulled toward the ground, where it becomes compressed and increases in temperature.

5 0

2 years ago

What is 93,000,000 in scientific notation?

DanielleElmas [232]

I believe it is 9.3x10^7

5 0

2 years ago

A. Based on the activation energies and frequency factors, rank the following reactions from fastest to slowest reaction rate, a

deff fn [24]

Answer:

A) $E_{a} = 350KJ/mol$ , $E_{a} = 50KJ/mol$ , $E_{a} = 50KJ/mol$

A = 1.5× $10^{-7}s^{-1}$ , A = 1.9× $10^{-7} s^{-1}$ , A=1.5× $10^{-7} s^{-1}$

B) 4.469

Explanation:

From Arrhenius equation

$K=Ae^{\frac{E_{a} }{RT} }$

where; K = Rate of constant

A = Pre exponetial factor

$E_{a}$ = Activation Energy

R = Universal constant

T = Temperature in Kelvin

Given parameters:

$E_{a} =165KJ/mol$

$T_{1}=505K$

$T_{2}=525K$

$R=8.314JK^{-1}mol^{-1}$

taking logarithm on both sides of the equation we have;

$InK=InA-\frac{E_{a} }{RT}$

since we have the rate of two different temperature the equation can be derived as:

$In(\frac{K_{2} }{K_{1} } )=\frac{E_{a} }{R}(\frac{1}{T_{1} } -\frac{1}{T_{2} } )$

$In(\frac{K_{2} }{K_{1} } )=\frac{165000J/mol}{8.314JK^{-1}mol^{-1} }.(\frac{1}{505} -\frac{1}{525} )$

$In(\frac{K_{2} }{K_{1} } )$ = 19846.04×7.544× $10^{-5}$ = 1.497

$\frac{K_{2} }{K_{1} }$ = $e^{1.497}$ = 4.469

6 0

2 years ago