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liq [111]
3 years ago
15

A machinist with normal vision has a near point at 25 cm. The machinist wears eyeglasses in order to do close work. The power of

the lenses is +1.75 diopters. With these eyeglasses, what is the near point of the machinist?
Physics
1 answer:
Alik [6]3 years ago
7 0

Answer:

17.4 cm

Explanation:

Power of lens = +1.75 diopters

Focal length of lens

f=\frac{100}{1.75}=\frac{400}{7}

This is a convex lens as focal the diopter given is positive which makes the focal length positive. Image distance will be negative.

v = -25

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\Rightarrow \frac{1}{-25}-\frac{1}{u}=\frac{1}{\frac{400}{7}}\\\Rightarrow -\frac{1}{u}=\frac{7}{400}+\frac{1}{25}\\\Rightarrow \frac{1}{u}=-\frac{7}{400}-\frac{1}{25}\\\Rightarrow \frac{1}{u}=-0.0575\\\Rightarrow u=-17.4\ cm

∴ The new near point is 17.4 cm

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For your student who dropped an object out of the window,

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When an object is dropped in Earth gravity,
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Answer:

Probability of tunneling is 10^{- 1.17\times 10^{32}}

Solution:

As per the question:

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Thickness of the tennis ball, t = 2.0 mm = 2.0\times 10^{- 3}\ m

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