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2 years ago

Easy one - giving brainly if correct.

Physics

1 answer:

lana66690 [7]2 years ago

4 0

Gas.

HOPE YOU GET 100!

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A spaceship accelerates from 0m/s to 40m/s in 5 seconds. What is the acceleration of the spaceship

nadya68 [22]

Acceleration = change in velocity/time
= 40/5
=8m/s^2

6 0

4 years ago

________ In many cartoon shows, a character runs off a cliff, realizes his predicament, and lets out a scream. He continues to s

IrinaVladis [17]

Answer:

Here the source is moving away from the observer so frequency will be smaller than the actual frequency and since the speed is increasing so the frequency is decreasing with time so correct answer is

D) lower than the original pitch and decreasing as he falls.

Explanation:

As we know by the Doppler's effect of sound we have

so we will have

$f = f_o(\frac{v}{v + v_s})$

so here when source moves away from the observer with a some speed then the frequency of the sound observed by the observer is smaller than the actual frequency

Here we know that the speed of the source is increasing with time as the source is falling under gravity

So we can say that the pitch of the sound will decrease with time

4 0

4 years ago

¿Hacia dónde se moverá el burro que se quiere sacar del corral jalándolo dos personas? La primer persona jala con 8 unidades de

dimaraw [331]

Answer:

sim eu também preciso desta respota

7 0

3 years ago

Find the velocity in m/s of a swimmer who swims 110m toward the shore in 72s

ruslelena [56]

S=Vt
110=V(72)
110/72=V
V=1.527m/s

4 0

3 years ago

The electric field in a region is uniform (constant in space) and given by E-( 148.0 1 -110.03)N/C. An additional charge 10.4 nC

enyata [817]

Answer:

The y-component of the electric force on this charge is $F_y = -1.144\times 10^{-6}\ N.$

Explanation:

<u>Given:</u>

Electric field in the region, $\vec E = (148.0\ \hat i-110.0\ \hat j)\ N/C.$
Charge placed into the region, $q = 10.4\ nC = 10.4\times 10^{-9}\ C.$

where, $\hat i,\ \hat j$ are the unit vectors along the positive x and y axes respectively.

The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

$\vec E = \dfrac{\vec F}{q}\\\therefore \vec F = q\vec E\\=(10.4\times 10^{-9})\times (148.0\ \hat i-110.0\ \hat j)\\=(1.539\times 10^{-6}\ \hat i-1.144\times 10^{-6}\ \hat j)\ N.$

Thus, the y-component of the electric force on this charge is $F_y = -1.144\times 10^{-6}\ N.$

3 0

3 years ago

Easy one - giving brainly if correct.​

Easy one - giving brainly if correct.