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raketka [301]
2 years ago
5

Easy one - giving brainly if correct.​

Physics
1 answer:
lana66690 [7]2 years ago
4 0

Gas.

HOPE YOU GET 100!

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Having the correct posture and the degree or severity of braking, acceleration and steering inputs have a direct result on the a
kaheart [24]

Answer: Vehicle Balance

Explanation:

Vehicle balance simply means how the weight of a vehicle is distributed across its tires which connects to the road

It should be noted that there'll be a shift in the balance of a vehicle when the braking, acceleration, or turning bring about a scenario in which the weight of th vehicle moves from one area to another.

8 0
3 years ago
A main sequence star cools and expands. It must be entering which stage?
aev [14]
If a main sequence star is cooling and expanding, it is entering the red giant stage. This means that the star has burned up all of it's hydrogen and is now starting to burn its helium making it cooler.
4 0
4 years ago
A force of 120 N is applied to an object whose mass is 30 kg. The object's acceleration is:
Airida [17]

Answer:

C) 4.0 m/s²

Explanation:

Given data

  • Applied force (F): 120 Newton
  • Mass of the object (m): 30 kilograms
  • Acceleration of the object (a): to be determined

We can find the acceleration of the object using Newton's second law of motion.

F = m . a

a = F / m = 120 N / 30 kg = 4.0 m/s²

The acceleration of the object is 4.0 m/s².

8 0
3 years ago
The nucleus of an atom contains positively charged particles, called protons, and neutral particles, called neutrons. How is the
11Alexandr11 [23.1K]

There exist a attractive force called nuclear force due to whixh nucleus is held together.It acts only to a very small distance

3 0
4 years ago
Read 2 more answers
The Starship Enterprise speeds past an asteroid at 0.920c. If an observer on the asteroid sees 10.0 seconds pass on her watch, h
lukranit [14]

Answer:

25.52 seconds

Explanation:

Speed of space ship = 0.92 c = v

c = Speed of light

Time observed from asteroid = Δt = 10 seconds

Time dilation

\Delta t'=\frac{\Delta t}{\sqrt{1-\frac {v^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-\frac {0.92^2c^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-0.92^2}}\\\Rightarrow \Delta t'=25.52\ s

∴ Time interval be if measured by an observer on the Enterprise would be 25.52 seconds

5 0
4 years ago
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