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2 years ago

Easy one - giving brainly if correct.

Physics

1 answer:

lana66690 [7]2 years ago

4 0

Gas.

HOPE YOU GET 100!

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How much mili ampere is 2 ampere

Rasek [7]

Answer:

2000 mili ampere

Explanation:

1 ampere is = to 1000 miliampere so 2 x 1000 is equal to 2000 miliampere

8 0

3 years ago

What is social participation? Why is it important for socialization?

Phantasy [73]

It is the intervention of citizens in decision-making regarding the management of resources and actions that have an impact on the development of their communities.

8 0

3 years ago

A dog is running at 15 m/s and then slows down to 10 m/s. It takes him two seconds to do this. What is the dog's acceleration

OLga [1]

Explanation:

a = (Vf-Vi)/t

= (10m/s - 15m/s)/2s

a = -5 / 2 m/s^2

• so the dog diaccelerate at the rate of 5/2 m/s^2

hope it helps

6 0

3 years ago

Two points charges are brought closer together,increasing the force between them by a factor of 25.By what factor wa their separ

Roman55 [17]

Answer:

The separation between the charges was decreased by a factor of 0.2

Explanation:

The Coulomb's force between two charges is given by;

$F = \frac{kq^2}{r^2} \\\\let \ kq^2 \ be \ constant\\\\F_1r_1^2 = F_2r_2^2\\\\r_2^2 = \frac{F_1r_1^2}{F_2} \\\\increasing \ the \ force \ between \ them \ by \ factor \ of \ 25\\\\(F_2 = 25F_1)\\\\r_2^2 = \frac{F_1r_1^2}{25F_1}\\\\r_2^2 = \frac{r_1^2}{25}\\\\r_2 = \sqrt{\frac{r_1^2}{25} }\\\\ r_2 = \frac{r_1}{5}$

r₂ = 0.2r₁

Therefore, the separation between the charges was decreased by a factor of 0.2.

6 0

3 years ago

A certain lightbulb has a tungsten filament with a resistance of 20.3 Ω when at 20.0°C and 135 Ω when hot. Assume the resistivit

Paladinen [302]

Answer:

1275.61° C

Explanation:

The resistance of a conductor varies as a function of temperature and it is given as follows

$R= R_o[1+\alpha(T-T_0)]$

R_0 is the resistance at temperature T_0, R is the resistance at T and α is the coefficient of temperature of resistance

α= 0.0045/°C

R_0 = 20.3Ω T_0 = 20°C and R= 135Ω

$135= 20.3[1+0.0045(T-20)]$

T= 1275.61° C

Therefore the temperature of the hot filament = 1275.61° C

3 0

4 years ago

Easy one - giving brainly if correct.​

Easy one - giving brainly if correct.