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tankabanditka [31]

3 years ago

12

the sun transfers heat to earth through _ this method of heat transfer is evidence that _ is not necessary for heat to move

from place to place

1 answer:

Maksim231197 [3]3 years ago

8 0

Answer:

electromagnetic waves, physical contact

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A mover does 422 J of work pushing a crate 8.39 m. How much force did he exert?

kicyunya [14]

Answer:

50.3N

Explanation:

Work done = force x distance

422J. = force x 8.39m

÷8.39 both side to get force

Force is 50.3N to 1 d.p.

Check:

50.3 x 8.39=422.017J

Same as 422J to 1 d.p

4 0

2 years ago

Read 2 more answers

The gauge pressure in the tires of your car is 210 kPa (30.5 psi) when the temperature is 25°C (77 °F). Several days later it is

DaniilM [7]

Under the assumption that the tires do not change in volume, apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 210kPa + 101.325kPa

P = 311.325kPa (add 101.325 to change gauge pressure to absolute pressure)

T = 25°C = 298.15K

Final P and T values:

P = ?, T = 0°C = 273.15K

Set the initial and final P/T values equal to each other and solve for the final P:

311.325/298.15 = P/273.15

P = 285.220kPa

Subtract 101.325kPa to find the final gauge pressure:

285.220kPa - 101.325kPa = 183.895271kPa

The final gauge pressure is 184kPa or 26.7psi.

8 0

3 years ago

A 12.5843-gram sample of metal bromide, MBr4, was dissolved and, after reaction with silver nitrate, AgNO3, all of the bromide w

barxatty [35]

Answer:

zirconium

Explanation:

Given, Mass of AgBr(s) = 23.0052 g

Molar mass of AgBr(s) = 187.77 g/mol

The formula for the calculation of moles is shown below:

$Moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles\ of\ AgBr= \frac{23.0052\ g}{187.77\ g/mol}$

$Moles\ of\ AgBr= 0.1225\ mol$

The reaction taking place is:

$MBr_4+4AgNO_3\rightarrow 4AgBr+M(NO_3)__4$

From the reaction,

4 moles of AgBr is produced when 1 mole of $MBr_4$ undergoes reaction

1 mole of AgBr is produced when 1 / 4 mole of $MBr_4$ undergoes reaction

0.1225 mole of AgBr is produced when $\frac {1}{4}\times 0.1225$ mole of $MBr_4$ undergoes reaction

Moles of $MBr_4$ got reacted = 0.030625 moles

Mass of the sample taken = 12.5843 g

Let the molar mass of the metal = x g/mol

So, Molar mass of $MBr_4$ = x + 4 × 79.904 g/mol = 319.616 + x g/mol

Thus,

$0.030625 = \frac{12.5843}{319.616 + x}$

Solve for x,

we get, x = 91.2999 g/mol

<u>The metal shows +4 oxidation state and has mass of 91.2999 g/mol . The metals is zirconium.</u>

8 0

2 years ago

hallar un numero de dos cifras sabiendo que la suma de las cifras es 12 y que la primera de ellas es el triple de la segunda

Natali [406]

Answer:

93 o 39.

Explanation:

Hola.

En este caso, podemos resolver este problema por medio del planteamiento de las siguientes ecuaciones:

1. Definimos <em>x</em> como el primer dígito y <em>y</em> como el segundo, por lo tanto, como su suma es 12, escribimos:

<em>x</em> + <em>y</em> = 12

2. Ahora, dado que el primer dígito, x es el triple del segundo, escribimos:

<em>x</em> = 3 <em>y</em>

De este modo, podemos resolver para <em>y</em>:

3 <em>y</em> + <em>y</em> = 12

4 <em>y</em> = 12

<em>y</em> = 12 / 4

<em>y</em> = 3

Y para <em>x</em>:

<em>x</em> = 3 <em>y</em>

<em>x</em> = 3 * 3

<em>x</em> = 9

Así, el número puede ser 93 o 39.

¡Saludos!

3 0

2 years ago

An element's atomic number is 25. How many protons would an atom of this element have?

s344n2d4d5 [400]

An element's "Atomic number" IS the number of protons
in the nucleus of each atom of the element.

If an element's Atomic number is 25, then it must follow ...
as the night follows the day ... that each atom of this element
has 25 protons in its nucleus. If it has a different number of
protons in its nucleus, then it's an atom of a different element.

7 0

2 years ago