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3 years ago

Someone please help will mark as brainliest

Chemistry

1 answer:

ohaa [14]3 years ago

5 0

Answer:

Adding more solute would increase the concentration.

Explanation:

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harina [27]

that seems very false but I believe its the second one

7 0

3 years ago

Read 2 more answers

Check all that apply to sugar.

harina [27]

Answer:

Candy

Explanation:

its sweet and has a lot of sugar and acid

3 0

3 years ago

Read 2 more answers

A solid is crushed into a powder is chimacal change or pysical change

SSSSS [86.1K]

Answer:

Physical Change

Explanation:

A solid being crushed into a powder is a physical change because a chemical change is when substances combine to create new substances.

Hope this helps :)

4 0

2 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

Tpy6a [65]

Answer : The percent purity of $Fe_2O_3$ in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

$Fe_2O3+3CO\rightarrow 2Fe+3CO_2$

First we have to calculate the mass of Fe.

$\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}$

Molar mass of Fe = 55.8 g/mole

$\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole$

Now we have to calculate the moles of $Fe_2O_3$

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of $Fe_2O_3$

So, $3.15\times 10^4mole$ of Fe produced from $\frac{3.15\times 10^4}{2}=15750$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3$

Molar mass of $Fe_2O_3$ = 159.69 g/mole

$\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg$

Now we have to calculate the percent purity of $Fe_2O_3$ in the original sample.

Mass of original sample = $2.86\times 10^3kg$

$\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100$

$\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%$

Therefore, the percent purity of $Fe_2O_3$ in the original sample is 87.94 %

3 0

2 years ago

A baker has two identical cakes except that one cake is hot, and the other cake is room temperature. He places both cakes on an

hjlf

Answer:

the plate gets warmer and the cake gets colder

Explanation:

my brain

4 0

3 years ago