Question

Big Bob is on his Harley and moving at 14.0m/s. He then accelerates to a velocity of 25m/s over a distance of 0.250 km. What is Big Bob’s acceleration?

Answer 1

As we know that it has all given data given as

$v_i = 14 m/s$

$v_f = 25 m/s$

distance moved = 0.250 km = 250 m

now we can use kinematics to find acceleration

$v_f^2 - v_i^2 = 2 a d$

$25^2 - 14^2 = 2 * a * 250$

$a = 0.86 m/s^2$

so it will accelerate at rate of 0.86 m/s^2