All categories

3 years ago

A book that weighs 16N is on top of a shelf that is 3m high. What is the work required to

Physics

1 answer:

DENIUS [597]3 years ago

8 0

48J

Explanation:

Given parameters:

Weight of the book = 16N

Height of the shelf = 3m

Unknown:

Work done to raise the book = ?

Solution:

Work done is defined as the product of force and distance. The force here is the weight of the book which signifies that it was carried in the vicinity of gravitational force.

Work done = Force x distance = weight x distance

Weight is a type of force;

Input the parameters;

Work done = 16 x 3 = 48J

The unit of workdone is in Joules

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

You might be interested in

The distance from the sun to the Earth is 1.5 x 1011 m. How long does it take for light from the sun to reach the earth? Give yo

Mariulka [41]

499.00 seconds or 8 min 20 sec

4 0

3 years ago

Read 2 more answers

A moving object has a kinetic energy of 150 j and a momentum with a magnitude of 30.0 kg•m/s. determine the mass and speed of th

SOVA2 [1]

To determine the answer to this item, we use two (2) equations.

Equation for kinetic energy:
KE = 0.5 mv²

Equation for momentum:
P = mv

From the second equation, we can deduced that,
m = P/v
Substituting the known values from the given above,

m = 30/v

Using this expression in the first equation,

KE = 0.5 mv²; 150 = 0.5(30/v)(v²)

The value of v from the equation is 10 m/s.

The mass is therefore calculated as such,
m = 30/v = 30/10 = 3 kg

Hence, the answers are,

<em> Mass = 3 kg</em>
<em> Velocity = 10 m/s</em>

4 0

3 years ago

HELP I WILL GIVE BRAINLIEST!

Ann [662]

Answer:

Answer:B

Explanation:

Because it all stayed consistant

4 0

3 years ago

What is the difference between balanced forces and action-reaction forces

Free_Kalibri [48]

when a number of force acting on a body doesn't changes its motion it is called balanced force

6 0

3 years ago

A square coil, enclosing an area with sides 2.0 cm long, is wrapped with 2 500 turns of wire. A uniform magnetic field perpendic

Delvig [45]

Answer:

The induced voltage in the coil is 0.25 V.

Explanation:

It is given that,

Area of a square coil is 2 cm or 0.02 m

Number of turns in the wire is 2500

A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.

We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,

$\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=NA\dfrac{-dB}{dt}\\\\\epsilon=-2500\times (0.02)^2\times \dfrac{0.25}{1}\\\\\epsilon=-0.25\ V$

So, the induced voltage in the coil is 0.25 V.

3 0

3 years ago