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kvasek [131]
3 years ago
9

A single-engine helicopter has two rotors; a main rotor and a tail rotor. The main rotor has a diameter of 14.4 m and rotates at

the rate of 450 rev/min while the tail rotor with a diameter of 1.6 m rotates at 4100 rev/min. What are the speeds, in m/s, of the tips of each rotor? main rotor speed m/s tail rotor speed m/s
Physics
1 answer:
Ber [7]3 years ago
6 0

Answer:

339.12 m/s, 343.31 m/s

Explanation:

For main rotor

diameter, d = 14.4 m

radius, r = 7.2 m

f = 450 rev/min = 450 / 60 = 7.5 rps

Angular speed, ω = 2 x π x f = 2 x 3.14 x 7.5 = 47.1 rad/s

linear speed, v = r x ω = 7.2 x 47.1 = 339.12 m/s

For tail rotor

diameter, d = 1.6 m

radius, r = 0.8 m

f = 4100 rev/min = 4100 / 60 = 68.33 rps

Angular speed, ω = 2 x π x f = 2 x 3.14 x 68.33 = 429.13 rad/s

linear speed, v = r x ω = 0.8 x 429.13 = 343.31 m/s

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slava [35]

Answer:

energy cannot be created or destroyed

Explanation:

Energy can't be created nor destroyed; rather, it transforms from one form to another.

8 0
3 years ago
Assuming that the limits of the visible spectrum are approximately 380 and 700 nm, find the angular range of the first-order vis
ch4aika [34]

Answer:

angular range is ( 0.681 rad , 0.35 rad )

Explanation:

given data

wavelength λ = 380 nm = 380 × 10^{-9} m

wavelength λ  = 700 nm =  700 × 10^{-9} m

to find out

angular range of the first-order

solution

we will apply here slit experiment equation that is

d sinθ = m λ    ...........1

here m is 1 for single slit and d is = \frac{1}{900*10^3 m}

so put here value in equation 1 for 380 nm

we get

d sinθ = m λ

\frac{1}{900*10^3} sinθ = 1 × 380 × 10^{-9}

θ = 0.35 rad

and for 700 nm

we get

d sinθ = m λ

\frac{1}{900*10^3} sinθ = 1 × 700 × 10^{-9}

θ = 0.681 rad

so angular range is ( 0.681 rad , 0.35 rad )

3 0
4 years ago
If you were on the open ocean on a large ship, what steps would you do to determine the height of a wave?
Daniel [21]
The first step to take is to check the anemometer to determine the intensity of the wind blowing in the open ocean. The measurement is in terms of knots or nautical miles. Next, we use a Beaufort scale to check what range the knots falls in. Using the scale, we can see what is the height of the wave. The Beaufort scale is used in open oceans only
3 0
3 years ago
How does a physicist answer a scientific question?
egoroff_w [7]

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He does an experment.

6 0
3 years ago
A 920-kg compact car moving at 92 m/s has approximately 3,893,440 Joules of kinetic energy. What is the change in kinetic energy
tensa zangetsu [6.8K]

Answer:

Change in kinetic energy = 3297280 J

Explanation:

Given that,

Mass, m = 920 kg

Speed of a car, v = 92 m/s

Kinetic energy, K = 3,893,440 J

If the speed of a car, V = 36 m/s

Net kinetic energy is given by :

K_n=\dfrac{1}{2}mV^2\\\\=\dfrac{1}{2}\times 920\times (36)^2\\\\K_n=596160\ J

The change in kinetic energy = 3,893,440 - 596160

= 3297280 J

So, the change in kinetic energy of the car is 3297280 J.

3 0
3 years ago
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