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kvasek [131]
3 years ago
9

A single-engine helicopter has two rotors; a main rotor and a tail rotor. The main rotor has a diameter of 14.4 m and rotates at

the rate of 450 rev/min while the tail rotor with a diameter of 1.6 m rotates at 4100 rev/min. What are the speeds, in m/s, of the tips of each rotor? main rotor speed m/s tail rotor speed m/s
Physics
1 answer:
Ber [7]3 years ago
6 0

Answer:

339.12 m/s, 343.31 m/s

Explanation:

For main rotor

diameter, d = 14.4 m

radius, r = 7.2 m

f = 450 rev/min = 450 / 60 = 7.5 rps

Angular speed, ω = 2 x π x f = 2 x 3.14 x 7.5 = 47.1 rad/s

linear speed, v = r x ω = 7.2 x 47.1 = 339.12 m/s

For tail rotor

diameter, d = 1.6 m

radius, r = 0.8 m

f = 4100 rev/min = 4100 / 60 = 68.33 rps

Angular speed, ω = 2 x π x f = 2 x 3.14 x 68.33 = 429.13 rad/s

linear speed, v = r x ω = 0.8 x 429.13 = 343.31 m/s

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snow_lady [41]

Answer:

Length (l) = 6 m

height (h) = 3 m

Load(L) = 500 N

Effort (E) = ?

we know the principal that

E * l = L * h

6 E = 500 * 3

6E = 1500

E = 250

therefore 250 N work is done on the barrel.

8 0
4 years ago
How effectiveness of a small force is increased when action area of force is<br> reduced?
STatiana [176]

Answer:

The force is proportional to the area, for if we increase the area but keep the number of molecules per cubic centimeter the same, we increase the number of collisions with the piston in the same proportion as the area was increased.

Explanation:

more area =more space = more free for molecules = less pressure = less force.

3 0
3 years ago
The mean distance of an asteroid from the Sun is 2.98 times that of Earth from the Sun. From Kepler's law of periods, calculate
lutik1710 [3]

Answer:

The asteroid requires 5.14 years to make one revolution around the Sun.

Explanation:

Kepler's third law establishes that the square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit:

T^{2} = a^{3} (1)

Where T is the period of revolution and a is the semi-major axis.

In the other hand, the distance between the Earth and the Sun has a value of 1.50x10^{8} Km. That value can be known as well as an astronomical unit (1AU).

But 1 year is equivalent to 1 AU according with Kepler's third law, since 1 year is the orbital period of the Earth.

For the special case of the asteroid the distance will be:

a = 2.98(1.50x10^{8}Km)

a = 4.47x10^{8}Km

That distance will be expressed in terms of astronomical units:

4.47x10^{8}Km.\frac{1AU}{1.50x10^{8}Km} ⇒ 2.98AU

Finally, from equation 1 the period T can be isolated:

T = \sqrt{a^{3}}

T = \sqrt{(2.98)^{3}}  

T = \sqrt{26.463592}

T = 5.14AU

Then, the period can be expressed in years:

5.14AU.\frac{1yr}{1AU} ⇒ 5.14 yr

T = 5.14 yr

Hence, the asteroid requires 5.14 years to make one revolution around the Sun.

8 0
3 years ago
sam can study for hours even though it is very loud and there are many possible distractions in the common room. this is an exam
Nostrana [21]

Sam can study for hours even though it is very loud and there are many possible distractions in the common room, this is an example of a Focus system.

The focus system is a psychological intervention that is purposely designed for use at home or in lecture halls for cognitive or mental assimilation.

When the focus system takes place, an individual is able to further activate the brain networks to engage in more challenging cognitive activities despite the music, distractions, or noise from the background.

From the information given, the ability for Sam to study for hours even though it is very loud was his ability to activate his Focus System.

Learn more about Cognitive ability here:

brainly.com/question/18994513?referrer=searchResults

5 0
3 years ago
Aluminum has a coefficient of linear expansion of 2.4x10^-5 C^-1 and a coefficient of volume expansion of 7.2x10^-5 C^-1. An alu
Alla [95]

Answer:

New length = 10.2 m

Explanation:

Let ΔL  = change in length

     ΔT = change in the temperature

     L(0) = intial length

     α = coeffient of linear expansion

Then

ΔL = αL(0)ΔT

    =(2.4×10^-5)(10)(100-20)

    =0.0192 m

New length = L(0) + ΔL

                   = 10 + 0.0192

                   = 10.2 m

6 0
3 years ago
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