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aleksandr82 [10.1K]
4 years ago
8

How would the dx2−y2 orbital in the n=5 shell compare to the dx2−y2 orbital in the n=3 subshell?the contour of the orbital would

extend further out along the x and y axes.the value of ℓ would increase by 2.the radial probability function would include two more nodes.the orientation of the orbital would be rotated 45∘ along the xy plane.the mℓ value would be the same.drag the appropriate items to their respective bins?
Physics
1 answer:
forsale [732]4 years ago
8 0
<span>Answer: True: A, C, E False: B, D The following representation of this orbital, 5dx2â’y2, depicted when it is bisected by the xy plane, shows the effect of the radial nodes on the orbital contours.</span>
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In which parts of a plant would u expect phototropism to occur?
Lubov Fominskaja [6]

Answer:

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Explanation:

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3 0
3 years ago
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Consider a concave spherical mirr or that has focal length f = +19.5 cm.
lidiya [134]

The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

<h3>What is concave mirror?</h3>

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

<h3>Object distance of the concave mirror</h3>

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

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  • v is the object distance
  • u is the image distance

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

Learn more about concave mirror here: brainly.com/question/27841226

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7 0
2 years ago
Which scenarios are examples of physical changes? Select three options
pashok25 [27]

Answer:

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need a picture to answer specific questions.

Explanation:

All of these are physical changes. Hope that this helps you and have a great day :)

4 0
3 years ago
a light ray traveling in air enters a second medium and its speed slows to 1.71 × 10^8 meters per second. what is the absolute i
givi [52]
The absolute refractive index is equal to the speed of light of the wave in air divided by the speed of light in the second medium. This means that it is equal to 3 x10^8 / 1.71 x10^8. This means the answer is 1.75
8 0
3 years ago
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When a force of 20.0N is applied to a spring, it elongates 0.20m. Determine the period of oscillation of a 4.0kg object suspende
choli [55]
So what we can do is apply the<span> Hooke's law wich states that
F = -kx ( P.S the -ve sign means opposite in direction ) 
Also we will need to determine the spring's constant with the formula:
k = F / x 
Where F = the force ( = 20 N ) 
x = the displacement of the end of the spring from it's position ( = 0.20 m ) 
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Hope it helps</span>
7 0
3 years ago
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