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3 years ago

What energy happens when you plug in a blender?

Physics

2 answers:

Dvinal [7]3 years ago

8 0

Answer:

Electrical to kinetic

Explanation:

ohaa [14]3 years ago

5 0

Answer:

Electrical energy is supplied to the blender.

Explanation:

This is converted into kinetic energy to turn the blades that blend the food, so energy is transferred from electrical to kinetic.

This is the useful energy change that we most want to happen.

You're welcome, have a good day :)

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A behavior that is developed by observing others or being taught is

Anit [1.1K]

B. Learned behavior

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3 years ago

Read 2 more answers

A satellite of mass 5600 kg orbits the Earth and has a period of 6200 s.

Troyanec [42]

Answer:

(a) Radius of orbit will be $=7.32\times10^6m$

(b) Earth gravitational force will be $=4.18\times 10^4N$

Explanation:

We have given

Mass of the earth, $M=6\times 10^{24}kg$

Mass of the satellite, m = 5600 kg

Radius of earth, $R=6.4\times 10^6m$

Time period T = 6200 sec

We know that $\omega =\frac{2\pi }{T}=\frac{2\times 3.14}{6200}=0.00101rad/sec$

Now

(a) We know that $\omega ^2=\frac{GM}{R^3}$

$R^3=\frac{GM}{\omega ^2}$

$R^3=\frac{6.67\times 10^{-11}\times 6\times 10^{24}}{0.00101 ^2}$

$R^3=3.92\times 10^{20}$

Radius of the orbit $R=7.32\times 10^6m$

(b)

Force $F=\frac{GMm}{R^2}=\frac{6.67\times 10^{-11}\times 6\times 10^{24}\times 5600}{(7.32\times 10^6)^2}=4.18\times 10^4N$

(c)

Altitude $h=radius\ of\ orbit-radius\ of\ earth=7.32\times 10^6-6.4\times 10^6=0.92\times 10^6m$

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3 years ago

How is science controlled by the government?

earnstyle [38]

Answer:

The answer is B

Explanation:

There are many Federal laws that help government tell scientist what is ethical and unethical.

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3 years ago

Which quantity is represented by the area under a force-time graph?

Yanka [14]

Answer:

C momentum change

Explanation:

An impulse results in a change of momentum.

An impulse is a force action over a period of time.

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3 years ago

A long wire is known to have a radius greater than 4.0 mm and to carry a current uniformly distributed over its cross section. i

ollegr [7]

Magnetic field outside it due to long wire is given by

$B = \frac{u_o i}{2 \pi r}$

Magnetic field due to long wire inside wire at any point

$B = \frac{u_o i r}{2 \pi R^2}$

Now the ratio of two magnetic field is given by

$\frac{B_{in}}{B_{out}} = \frac{r_1/R^2}{1/r_2}$

$\frac{0.285}{0.200} = \frac{4*10}{R^2}$

$1.425 = \frac{40}{R^2}$

R = 5.3 mm

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3 years ago