Answer:
linear charge density = -9.495 ×
C/m
Explanation:
given data
revolutions per second = 1.80 ×
radius = 1.20 cm
solution
we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force
so
- q × E = m × w² × r ..................1
- 9 ×
×
q = m × w² × r ............2
and w =
w =
w = 1.80 ×
×
w = 11304000 rad/s
so here from equation 2
- 9 ×
×
1.80 ×
= 1.672 ×
× 11304000² × 0.0120
linear charge density = -9.495 ×
C/m
As you mentioned, we will use <span>Equipartition Theorem.
</span><span>H2 has 5 degrees of freedom; 3 translations and 2 rotation
</span>Therefore:
Internal energy = (5/2) nRT
You just substitute in the equation with the values of R and T and calculate the internal energy as follows:
Internal energy = (5/2) x 2 x <span>8.314 x 308 = 32.0089 x 10^3 J</span>