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2 years ago

8

A driver of a car traveling at 15.0 m/s applies the brakes, causing a uniform acceleration of -2.0 m/s² and a final velocity of

10.0 m/s. How far has the car moved during this acceleration?

1 answer:

Vika [28.1K]2 years ago

8 0

Do you have the answer for this question? so i can provide u solution more effectively

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Which of the following would be the SI unit to use in measuring the temperature of hot liquid

GREYUIT [131]

Answer:

Kelvin

Explanation:

The SI unit to use in measuring the temperature of hot liquid is kelvin (K)

7 0

3 years ago

A certain metal wire has a cross sectional area of 1 mm2 and is 1 m long. when it is hung from the ceiling and a 10 kg mass is h

kvasek [131]

From the Hooke's law , the extension force of an elastic material is directly proportional to the extension.
That is, F = k e, where F is the force , k is the constant and e is the extension
F = 10 × 10 = 100 N
e = 1mm or 0.001 m
Hence, k = F/e
= 100 N/ 0.001
= 100000 N/m or 100 N/mm

5 0

3 years ago

A force F is used to raise a 4-kg mass M from the ground to a height of 5 m. What is the work done by the force F? (Note: sin 60

miskamm [114]

Answer:

Answer:196 Joules

Explanation:

Hello

Note: I think the text in parentheses corresponds to another exercise, or this is incomplete, I will solve it with the first part of the problem

the work is the product of a force applied to a body and the displacement of the body in the direction of this force

assuming that the force goes in the same direction of the displacement, that is upwards

W=F*D (work, force,displacement)

the force necessary to move the object will be

$F=mg(mass *gravity)\\F=4kgm*9.8\frac{m}{s^{2} }\\ F=39.2 Newtons\\replace\\\\W=39.2 N*5m\\W=196\ Joules$

Answer:196 Joules

I hope it helps

5 0

3 years ago

An airplane accelerates from rest down a runway at 3.20 m/s2 for 32.8 seconds until it lifts off the ground. Determine the dista

vagabundo [1.1K]

Answer:

s=1721.344m ,v=104.96m/s.

Explanation:

using thr equation of motion;

$s=ut+\frac{1}{2}at^{2}$

u=0, plane starts from rest,

$s=\frac{1}{2}at^{2}$

$a=3.2m/s^{2}, t=32.8s \\ s=\frac{1}{2}*3.2*32.8^{2}$

s=1721.344m

v=u+at

v=0 +3.2*32.8

v=104.96m/s

8 0

3 years ago

goblinko [34]

Answer:

Explanation:

initial velocity u = 32.7 m /s

final velocity v = 50.3 m /s

displacement s = 44500 m

acceleration a = ?

v² = u² + 2 a s

50.3² = 32.7² + 2 x a x 44500

2530.09 = 1069.29 + 89000a

a .016 m /s²

time taken t = ?

v = u + at

50.3 = 32.7 + .016 t

t = 1100 s

6 0

2 years ago