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Sergeeva-Olga [200]
3 years ago
12

Hen Mount St. Helen's erupted in 1980, it sent volcanic ash 18 kilometers into Earth's atmosphere. Which portions of Earth's atm

osphere were contaminated by the volcanic ash?
Physics
1 answer:
Andrew [12]3 years ago
8 0

Answer:

Astronomical location of Mount St. Helen's is 46°12′01″N 122°11′22″O, meaning that such statovolcano is located at middle latitudes. In middle latitudes, troposphere is 17 kilometers high, which is below stratosphere, whose height is 10 kilometers at middle latitudes. Hence, the eruption of Mount St. Helen's in 1980 contiminated troposphere and lower parts of stratosphere due to volcanic ash.

Explanation:

Astronomical location of Mount St. Helen's is 46°12′01″N 122°11′22″O, meaning that such statovolcano is located at middle latitudes. In middle latitudes, troposphere is 17 kilometers high, which is below stratosphere, whose height is 10 kilometers at middle latitudes. Hence, the eruption of Mount St. Helen's in 1980 contiminated troposphere and lower parts of stratosphere due to volcanic ash.

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C.) The measuring unit of "Electrical Power" is "Watt"

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3 years ago
Holding onto a tow rope moving parallel to a frictionless ski slope, a 70.1 kg skier is pulled up the slope, which is at an angl
lara [203]

Answer:

given,

mass of the skier = 70.1 Kg

angle with horizontal, θ = 8.6°

magnitude of the force,F = ?

a) Applying newton's second law

   m g sin\theta - F_{rope} = ma

 velocity is constant, a = 0

   m g sin\theta - F_{rope} =0

   F_{rope} = m g sin\theta

   F_{rope} = 70.1\times 9.8\times sin 8.6^0

  F_{rope}= 102.73\ N

b) now, when acceleration, a = 0.135 m/s²

   F_{rope}-m g sin\theta = ma

 velocity is constant, a = 0.135 m/s₂

   F_{rope} = m g sin\theta+ma

   F_{rope} = 70.1\times 9.8\times sin 8.6^0+70.1\times 0.135

  F_{rope}= 112.19\ N

7 0
3 years ago
A student who was training for a cross country race jogged for 2. 0 hours and covered a distance of 14. 0 kilometers. What was t
FinnZ [79.3K]

The average speed is 116.66m/s.

Given - The path traced is 14km , time for jogging is 2 hrs=120min

To find the average speed-

  1. Speed refers to the ease of the movement and degree of mobility as a result of force application.
  2. Due to this there is involvement of velocity.
  3. Journey of average speed is the cumulative of distances and time.
  4. Kinetic theory refers to the Boltzmann constant connecting to the standards of distance traversed.

calculations-

Speed= \frac{Distance}{Time}

Speed= 14 000 / 120

= 116.66m/s

To learn more about average speed -

<u>brainly.com/question/27753148</u>

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6 0
1 year ago
If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the
Reika [66]

Answer:

Vapors

Explanation:

We take into account that all the energy from the lightning has been transformed into steam.

\Delta U = Q -  W\\Q = mC \Delta T\\Q = mL

We calculate the amount of energy required by water to convert into steam.

Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J

Q_{change\ to\ steam} = 50 \times 2.256 \times 106 \\= 1.128 \times 10^8 \ J

Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J

From the lightning we received 10^{10} \ J of energy, out of which 1.126 \times 10^8 has been used to convert the water into steam.

Energy left = 10^{10} - 1.126 \times 10^8 = 9.88 \times 10^9 \ J

We use this energy to convert steam into vapors.

Q = \Delta E

Q = \Delta E = mc (T_{f} - T{i})\\T_{f} = \frac {\Delta E}{mc} + T_{i}\\ \\T_{f} = 100 + \frac{9.88 \times 10^{10}}{50 \times 1970}\\T_{f} = 100 + 10^8\\T_{f} = 10 ^{ \ 8} \ {^ \circ } C

With this temperature, we can easily interpret that the vapors will be dissociated in hydrogen and oxygen particles.

5 0
3 years ago
Normal body temperature. the average normal body temperature measured in the mouth is 310 k . what would celsius and fahrenheit
faltersainse [42]
The question is simply asking us to convert one unit, in this case temperature, to another unit. To do this, we need conversion factors to multiply, divide or relate to the original measurement. We do as follows:

Celsius = Kelvin - 273.15
310 - 273.15 = 36.85 degrees celsius

Fahrenheit = <span> (°</span>C<span> × </span>9<span>/5) + 32
</span> (36.85<span> × </span>9<span>/5) + 32 = 98.33 degrees fahrenheit
</span>
Hope this helps.

7 0
3 years ago
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