<span>We can use the heat
equation,
Q = mcΔT </span>
<span>
Where Q is the amount of energy transferred (J), m is
the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature
difference (°C).</span>
According to the given data,
Q = 300 J
m = 267 g
<span>
c = ?
ΔT = 12 °C</span>
By applying the
formula,
<span>300 J = 267 g x c x
12 °C
c = 0.0936 J g</span>⁻¹ °C⁻<span>¹
Hence, specific heat of the given substance is </span>0.0936 J g⁻¹ °C⁻¹.
Answer:
4.375 milligram
Explanation:
Applying,
A = A'(2ᵃ/ⁿ)............. Equation 1
Where A = original amount of actinium-228, A' = amount of actinium-228 left after decay, a = Total time, n = half life
make A' the subject of the equation
A' = A/(2ᵃ/ⁿ)........... Equation 2
From the question,
Given: A = 70 milligram, a = 24.52 hours, n = 6.13 hours
Substitute these values into equation 2
A' = 70/(2²⁴°⁵²/⁶°¹³)
A' = 70/(2⁴)
A' = 70/16
A' = 4.375 milligram
Answer:
there'd be 2 electrons
Explanation:
number of electrons= number of protons
