ΔG° = -RT ln K
ΔG° = -RT ln 1/Ksp (reverse reaction, solid (Al(OH)₃ not count for equilibrium constant-K)
ΔG° = -RT ln 1/Ksp
ΔG° = -8.314 x 10⁻³ x 298 ln 1/(2 x 10⁻³¹)
ΔG° = -175.132 kJ/mol
Answer:
c
Explanation:
was c the correct answer or not
A typical phase diagram has pressure on the y-axis and temperature on the x-axis. As we cross the lines or curves on the phase diagram, a phase change occurs. In addition, two states of the substance coexist in equilibrium on the lines or curves.Jun 6, 2016