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3 years ago

_HNO3+ Fe+2

Chemistry

1 answer:

ale4655 [162]3 years ago

4 0

Answer: The coefficient for water after the equation is balanced is 2.

Explanation:

The balanced chemical equation must have same charge and same number of atoms on both sides of the equation.

As the given reaction is a redox recation occuring in acidic medium.

$HNO_3+3Fe^{2+}+3H^+\rightarrow NO+3Fe^{3+}+2H_2O$

The coefficient for water will be 2 after the equation is balanced.

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Why is the formation of water a synthesis reaction?

lisabon 2012 [21]

Explanation:

A synthesis reaction: It is defined as a kind of reaction where one and more than one reactant attached and creates an individual product.

The formation of the water is an example of a synthesis reaction because here more than one reactants combine and create a single product (water). Water formation occurs when 2 hydrogens and an oxygen share electrons through covalent bonds.

2H + O ----> H2O.

7 0

3 years ago

Calculate the ph of a solution with a [H3O+]=5.6x10-9M

Kisachek [45]

Answer:

pH = 8.25

Explanation:

The acidity or basicity of a solution is measured by its pH. The pH scale ranges from 0 to 14. Solutions having pH from 0-6.9 are considered acidic, at 7 neutral and basic when ranging from 7.1-14.

pH is calculated as,

pH = - log [H⁺] ---- (1)

Where;

[H⁺] = concentration of Acid

Also, for bases pH i calculated using following formula,

pH = 14 - pOH

Therefore, Putting value of H⁺ in equation 1,

pH = - log [5.6 × 10⁻⁹]

pH = 8.25

The solution provided is basic in nature.

6 0

3 years ago

If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the res

baherus [9]

<u>Answer:</u> The molality of the solution is 0.1 m.

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute = 27.1 g

$M_{solute}$ = Molar mass of solute = 27.1 g/mol

$W_{solvent}$ = Mass of solvent = 100 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m$

Hence, the molality of the solution is 0.1 m.

8 0

3 years ago

Read 2 more answers

2 Points

levacccp [35]

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4 0

3 years ago

Read 2 more answers

A solution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the b

Finger [1]

Answer : The molar mass of the solute will be 87.90 g/mol.

Explanation : We know the formula for elevation in boiling point, which is

Δt = i $K_{b}$ m

given that, Δt = 0.357, $K_{b}$ = 5.02 and mass of $CCl _{4}$ = 40,

on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X $10^{-3}$ .
Now, 0.250/ 2.844 X $10^{-3}$ = 87.90 g/mol. which is the weight of unknown component.

3 0

3 years ago