A tennis player tosses a tennis ball straight up and then catches it after 1.77 s at the same height as the point of release. (a
1 answer:
(a) 9.8 m/s^2, downward
There is only one force acting on the ball while it is in flight: the force of gravity, which is
F = mg
where
m is the mass of the ball
g is the gravitational acceleration
According to Newton's second law, the force acting on the ball is equal to the product between the mass of the ball and its acceleration, so
F = mg = ma
which means
a = g
So, the acceleration of the ball during the whole flight is equal to the acceleration of gravity:
g = -9.8 m/s^2
where the negative sign means the direction is downward.
(b) v = 0
Any object thrown upward reaches its maximum height when its velocity is zero:
v = 0
In fact, at that moment, the object's velocity is turning from upward to downward: that means that at that instant, the velocity must be zero.
(c) 8.72 m/s, upward
The initial velocity of the ball can be found by using the equation:
v = u + at
Where
v = 0 is the velocity at the maximum height
u is the initial velocity
a = g = -9.8 m/s^2 is the acceleration
t is the time at which the ball reaches the maximum height: this is half of the time it takes for the ball to reach again the starting point of the motion, so
So we can now solve the equation for u, and we find:
(d) 3.88 m
The maximum height reached by the ball can be found by using the equation:
where
v = 0 is the velocity at the maximum height
u = 8.72 m/s is the initial velocity
a = g = -9.8 m/s^2 is the gravitational acceleration
d is the maximum height reached
Solving the equation for d, we find
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Answer:
Fnet = 14515.2 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
Where;
- Fnet is the net force.
- Fapp is the applied force.
- Fg is the force due to gravitation.
Given the following data;
Mass = 1,152 kg
Initial velocity, u = 3m/s
Final velocity, v = 17m/s
Time, t = 5 seconds
To find the magnitude of the net force;
First of all, we would determine the acceleration of the car.
Acceleration = (v-u)/t
Acceleration = (17 - 3)/5
Acceleration = 14/5
Acceleration = 2.8m/s
To find the applied force;
Fapp = mass * acceleration
Fapp = 1,152 * 2.8
Fapp = 3225.6 N
Next, we would find the force exerted on the car due to gravity.
Fg = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8m/s²
Fg = 1152 * 9.8
Fg = 11289.6N
Substituting the values into the equation, we have;
Fnet = 3225.6 + 11289.6
Fnet = 14515.2 Newton