<h3><u>Answer</u>;</h3>
= F0 L ( 1 - 1/e )
<h3><u>Explanation;</u></h3>
Work done is given as the product of force and distance.
In this case;
Work done = ∫︎ F(x) dx
= F0 ∫︎ e^(-x/L) dx
= F0 [ -L e^(-x/L) ] between 0 and L
= F0 L ( 1 - 1/e )
To solve this problem it is necessary to apply the concepts related to the geometry of a cylindrical tank and its respective definition.
The volume of a tank is given by

Where
d = Diameter
h = Height
Considering that there are two stages, let's define the initial and final volume as,


We know as well by definition that

Then we have for the statement that


Replacing the previous data


Solving to get h,

Therefore the change is



Therefore te change in the height of the water in the tank is 0.37mm
Answer:
1.7323
Explanation:
To develop this problem, it is necessary to apply the concepts related to refractive indices and Snell's law.
From the data given we have to:



Where n means the index of refraction.
We need to calculate the index of refraction of the liquid, then applying Snell's law we have:



Replacing the values we have:


Therefore the refractive index for the liquid is 1.7323
i will give you 25 points sorry becuase i can't help with that
Answer:
C. Horizontal component of velocity
Explanation:
Object in motion stays in motion,
nothing works against its motion in the horizontal direction, unlike in the vertical direction, gravity pulls object down.