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Vladimir [108]
3 years ago
14

If 3.95 g of N2H4 reacts and produces 0.750 L of N2, at 295 K and 1.00 atm, what is the percent yield of the reaction?

Chemistry
1 answer:
adell [148]3 years ago
3 0
Molar mass of N2H4 = 32 grams/mole 
<span>3.95 grams of  N2H4 = 3.95/32
                                  = 0.123 moles </span>

<span>This will produce 0.123 moles of N2 </span>
<span>Now,
From the gas law equation. </span>
<span>P.V = n x R x T </span>
<span>P = 1 atm (given)
V = </span><span>0.123</span><span> x 0.082057 x 295 </span>
<span>V = 2.97 Liters </span>

<span>Theoretical yield = 2.97 Liters.
Actual yield = 0.750 Liters </span>

percentage yield = (0.75/2.97) x 100 %
                           = 25.25 %
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inn [45]

Answer: The density of the unknown metal is 7.86 g/ml.

Explanation:

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density=\frac{25.32g}{3.22ml}

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what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro
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The change in the velocity = 4 m/s

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<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

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Required

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irga5000 [103]
As we have the balanced reaction equation is:

N2O4 (g) ↔ 2NO2(g)

from this balanced equation, we can get the equilibrium constant expression

KC = [NO2]^2[N2O4]^1

from this expression, we can see that [NO2 ] is with 2 exponent of  the stoichiometric and we can see that from the balanced equation as NO2
is 2NO2 in the balanced equation.

and [N2O4] is with 1 exponent of the stoichiometric and we can see that from the balanced equation as N2O4 is 1 N2O4 in the balanced equation. 

∴ the correct exponent for N2O4 in the equilibrium constant expression is 1 
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3 years ago
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