The options are labelled as:
1 2
3 4
5 6
7 8
Protons: 1, 5, 7
Neutrons: 2, 8
Electron: 3, 4, 6
Answer:
Sb and Te
Explanation:
there are on the stair step
Answer:
6.68 X 10^-11
Explanation:
From the second Ka, you can calculate pKa = -log (Ka2) = 6.187
The pH at the second equivalence point (8.181) will be the average of pKa2 and pKa3. So,
8.181 = (6.187 + pKa3) / 2
Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11
Answer: 1.91 moles
Explanation:
First you want to find the molar mass of NaCL
Na = 22.99g Cl = 35.45g
22.99g + 35.45g = 54.44g
Then divide 111.5g by 54.44g and this will give you moles.
Q1)
We have been given the OH⁻ concentration, therefore we first need to find the pOH value and then the pH value.
pOH = -log [OH⁻]
pOH = -log (0.225 M)
pOH = 0.65
pH + pOH = 14
pH = 14 - 0.65 = 13.35
Q2)
pOH = -log[OH⁻]
pOH = -log (0.0015 M)
pOH = 2.82
pH + pOH = 14
pH = 14 - 2.82
pH = 11.18