Why does adding lemon juice to a blueberry smoothie make it change color from purple to pink.

c) If a mixture of zinc powder and cobalt(II) oxide is heated, the following reaction occurs: Zn(s) + COO(s) → ZnO(s) + Co(s) (i

bazaltina [42]

Answer:

The metal which reduces the other compound is the one higher in reactivity. So in this case, it is.

Explanation:

5 0

2 years ago

A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?

horsena [70]

Answer: The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

Explanation:

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL$

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = $\frac{44g}{77.46mL}\times 60mL=34.1g$

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0

3 years ago

Explain why the Chemicals properties of Mg 24 12 and Mg 26 12 are the same

Volgvan

Answer:

both Mg isotopes have same atomic number which is equal to number of protons , and the chemical properties of an element depends upon the the number of protons in its atom . and both Mg 24 12 and Mg 26 12 have same number of protons hence they exhibits similar chemical

okay

Explanation:

i hope it helped you .

5 0

3 years ago

You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (p K a = 4.20 ) and 0.200 M sodium benzoate

bekas [8.4K]

Answer : The volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.

Explanation :

Let the volume of sodium benzoate (salt) be, x

So, the volume of benzoic acid (acid) will be, (100 - x)

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

Now put all the given values in this expression, we get:

$4.00=4.20+\log \left(\frac{(\frac{0.200x}{100})}{(\frac{0.100(100-x)}{100})}\right)$

x = 29.0

The volume of sodium benzoate = x = 29.0 mL

The volume of benzoic acid (acid) = (100 - x) = (100 - 29.0) = 71 mL

Thus, the volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.

5 0

3 years ago

For the reaction ? C6H6 + ? O2 → ? CO2 + ? H2O 42.5 grams of C6H6 are allowed to react with 113.1 grams of O2. How much CO2 will

ziro4ka [17]

Answer:

There will be 143,67g CO2 produced

Explanation:

2 C6H6 + 15 O2 → 12 CO2 + 6 H2O

(42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6

(113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2

0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.

(0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2

3 0

3 years ago