The characteristic of the compound you are referring is essential to where on the functional groups it belong. Furthermore, the basic functional groups among the hydrocarbons are: alkane, alkene, alkyne, benzene, and others that basically has a hydrogen atom and a carbon atom.
Answer:
Mercury, Earth, Saturn, Jupiter, and the sun
Explanation:
this is from smallest to largest. hope it helps
Answer:
Explanation:
Benzene is an example for six membered aromatic hydrocarbons
Answer:
9.25
Explanation:
Let first find the moles of
and ![NaOH](https://tex.z-dn.net/?f=NaOH)
number of moles of
= 0.40 mol/L × 200 × 10⁻³L
= 0.08 mole
number of moles of
= 0.80 mol/L × 50 × 10⁻³L
= 0.04 mole
The equation for the reaction is expressed as:
![NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}](https://tex.z-dn.net/?f=NH%5E%2B_%7B4%28aq%29%7D%20%5C%20%2B%20OH%5E-_%7B%28aq%29%7D%20------%3E%20NH_%7B3%28g%29%7D%20%5C%20%2B%20H_2O_%7B%28l%29%7D)
The ICE Table is shown below as follows:
![NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}](https://tex.z-dn.net/?f=NH%5E%2B_%7B4%28aq%29%7D%20%5C%20%2B%20OH%5E-_%7B%28aq%29%7D%20------%3E%20NH_%7B3%28g%29%7D%20%5C%20%2B%20H_2O_%7B%28l%29%7D)
Initial (M) 0.08 0.04 0
Change (M) - 0.04 -0.04 + 0.04
Equilibrium (M) 0.04 0 0.04
![K_a*K_b = 10^{-14} \ at \ 25^0C](https://tex.z-dn.net/?f=K_a%2AK_b%20%3D%2010%5E%7B-14%7D%20%5C%20at%20%5C%2025%5E0C)
![K_a = \frac{10^{-14}}{K_b}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B10%5E%7B-14%7D%7D%7BK_b%7D)
![K_a = \frac{10^{-14}}{1.76*10^{-5}}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B10%5E%7B-14%7D%7D%7B1.76%2A10%5E%7B-5%7D%7D)
![K_a= 5.68*10^{10}](https://tex.z-dn.net/?f=K_a%3D%205.68%2A10%5E%7B10%7D)
![pK_a = - log \ (K_a)](https://tex.z-dn.net/?f=pK_a%20%3D%20-%20log%20%5C%20%28K_a%29)
![pK_a = - log \ (5.68*10^{-10})](https://tex.z-dn.net/?f=pK_a%20%3D%20-%20log%20%5C%20%285.68%2A10%5E%7B-10%7D%29)
![pK_a = 9.25](https://tex.z-dn.net/?f=pK_a%20%3D%209.25)
for buffer solutions
since they are in the same solution
![pH = 9.25 + \ log (\frac{0.04 }{ 0.04} )](https://tex.z-dn.net/?f=pH%20%3D%209.25%20%2B%20%5C%20log%20%28%5Cfrac%7B0.04%20%7D%7B%200.04%7D%20%29)
![pH = 9.25](https://tex.z-dn.net/?f=pH%20%3D%209.25)
Answer:
option C is correct = 1.14 × 10²² molecules of CO₂
Explanation:
Given data:
Number of moles of CO₂ = 0.0189 mol
Number of molecules = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
For given question:
1 mole of CO₂ = 6.022 × 10²³ molecules of CO₂
0.0189 mol of CO₂ × 6.022 × 10²³ molecules of CO₂ / 1mol
1.14 × 10²² molecules of CO₂
Thus, option C is correct.