In neutralization reactions, a base and an acid react to form an ionic salt and water. There is a rule that when a strong base and a strong acid react, the pH of their salt is always neutral which is at pH 7. However, this is only true if equal amounts of acid and base are consumed and that there is no excess. Otherwise, the excess acidity or basicity will adjust the total pH.
Strong acids are the following: HCl, HBr, HI, HClO4, HClO3, HNO3 and H2SO4. Strong bases are KOH, LiOH, NaOH, Ca(OH)2, Sr(OH)2 and Ba(OH)2. Therefore, we can already establish that both of the reactants are strong. The complete reaction is
HBr + KOH ⇒ KBr + H₂O
So, 1 mole of HBr would require 1 mol of KOH, and vice versa. Let'scompute the amount of the initial reactants:
mol HBr: (0.25 mol/L)*(0.92 L) = 0.23 mol HBr
mol KOH: (0.5 mol/L)*(0.46 L) = 0.23 mol KOH
There are equal amounts of acid and base. Thus, pH of the KBr solution is neutral at pH 7.
Answer:
(a)
(b)
(c)
Explanation:
(a)
The given compound is silicon tetrabromide. It means that 1 silicon and four bromine atoms are combined to form the molecule.
The chemical formula of silicon tetrabromide is
(b)
The given compound is disulfur dichloride. It means that 2 sulfur atoms and 2 chlorine atoms are combined to form the molecule.
The chemical formula of disulfur dichloride is
(c)
The given compound is diphosphorus hexaoxide. It means that 2 phosphorus atoms and 6 oxygen atoms are combined to form the molecule.
The chemical formula of diphosphorus hexaoxide is
