Mass in kilograms of liquid air required = 0.78 kg
<u>Given that </u>
1 Litre of liquid air contains 1.3 grams of oxygen ( air )
<u />
<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>
volume of air given = 600 L
mass of liquid air required = x
1 litre = 1.3 grams
600 L = x
∴ x ( mass of liquid air ) = 1.3 * 600
= 780 g = 0.78 kg
Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg
Learn more about liquid air : brainly.com/question/636295
sorry but if you are looking for an answer I don't know one. :(
O.N. of Na = +1
O.N. of O = -2
Let, O.N. of Tin = x
1*2 + x + -2*2 = 0
2+x-4 = 0
x-2 = 0
x = 2
SO OPTION C IS YOUR ANSWER......
Answer:
Chemical Formula:
For example- for every one mole of the compound PCl3 P C l 3 , it contains 3 moles of Chlorine atom and 1 mole of Phosphorus atom.
Explanation:
• Phosphorus trichloride (PCl3) contains three chlorine atoms and one phosphorus atoms.
Answer:
I think copper
Explanation:
Material IACS % Conductivity
Silver 105
Copper 100
Gold 70
Aluminum 61
Nickel 22
Zinc 27
Brass 28
Iron 17
Tin 15
Phosphor Bronze 15
Lead 7
Nickel Aluminum Bronze 7
Steel 3 to 15
the table might help- your indian brother
