80.1 g* (1 cm^(3)/ 2.70 g)= 29.666666... cm^(3).
The calculated volume should have 3 significant figures, so the final answer is 2.97*10^(1) cm^(3)
Hope this helps~
Answer:
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Explanation:
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Answer:just for the ponits
Explanation:ima be a jenna
Answer:
A. 15859.2 L or 15900 L
B. 0.629 mol
Explanation:
At STP, one mole is equal to approximately 22.4 L
L or mL is volume, so you are attempting to solve for L or mL.
A.
708 mol x (22.4 L/1 mol) = 15859.2 L (w/ significant figures included - 15900 L)
B.
(14.1 L) x (1 mole/ 22.4 L) = 0.629 mol.
Answer:
12.7 mol
Explanation:
<em>A chemist measures the amount of fluorine gas produced during an experiment. He finds that 482. g of fluorine gas is produced. Calculate the number of moles of fluorine gas produced.</em>
Step 1: Given data
Mass of fluorine (m): 482. g
Step 2: Determine the molar mass (M) of fluorine
Fluorine is a diatomic molecule of chemical formula F₂. Its molar mass is:
mF₂ = 2 × mF = 2 × 19.00 g/mol = 38.00 g/mol
Step 3: Determine the number of moles (n) corresponding to 482. g of fluorine
We will use the following expression,.
n = m/M
n = 482. g/(38.00 g/mol)
n = 12.7 mol
