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4 years ago

How can you use probability to predict the outcome of a codominant cross?

1 answer:

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Calculate: Punnett squares can be used to predict probable outcomes of genetic crosses. To calculate probability, divide the number of one kind of possible outcome by the total number of all possible outcomes. For example, if you toss a coin, the chance it will land on heads is equal to 1 ÷ 2.

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Is Neon a metal, nonmetal, or a metalliod

natulia [17]

Neon is a nonmetal.....

5 0

3 years ago

Read 2 more answers

What happened to Mendeleev's mother after he was accepted into St. Petersburg University?

Rama09 [41]

Answer:

his mother died i think

Explanation:

Although he was not accepted, his mother was determined to give her son a first-class education and they walked to St. Petersburg. Dmitri was accepted into the Institute of Pedagogy on a full scholarship. That same year his mother died and at the age of sixteen, Dmitri was orphaned.

4 0

3 years ago

The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C

Kipish [7]

Answer: 72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Putting in the values we get:

$\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles$

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

According to stoichiometry:

1 mole of $C_3H_8$ requires 5 moles of oxygen

0.45 moles of $C_3H_8$ require= $\frac{5}{1}\times 0.45=2.25$ moles of oxygen

Mass of $O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g$

72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

7 0

3 years ago

What ions are associated with bases

Setler [38]

Hydroxide ions are what you are looking for. When hydroxide ions are released, the solution becomes more basic

4 0

4 years ago

Help plz this is part b to my last question

Elden [556K]

Answer:

% error Aluminum: 0.34%

% error Steel: 16.67%

% error Lead: 23.08%

Explanation: Given our observed values of specific heat, to find the % error, we must know the true values as well. % error can be defined as, % error = |observed value - true value | / true value.

Our given data to solve this problem is as follows:

Aluminum Specific Heat Observed Value: 0.9 (given), Aluminum Specific Heat True Value: 0.897 (research).

Steel Specific Heat Observed Value: 0.49 (given), Steel Specific Heat True Value: 0.42 (research).

Lead Specific Heat Observed Value: 0.16 (given), Lead Specific Heat True Value: 0.13 (research).

___________

Since we have all the information, just subtract the true value from the observed value, and divide by the true value.

Aluminum Specific Heat % error:

observed value - true value / true value →

0.9 - 0.897 / 0.897 = 0.003 / 0.897 = 1/299 ≈ 0.34 %

Steel Specific Heat % error:

observed value - true value / true value →

0.49 - 0.42 / 0.42 = 0.07 / 0.42 = 1/6 ≈ 16.67%

Lead Specific Heat % error:

observed value - true value / true value →

0.16 - 0.13 / 0.13 = 0.03 / 0.13 = 3/13 ≈ 23.08%

3 0

3 years ago