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Yanka [14]
3 years ago
10

Help plz this is part b to my last question​

Chemistry
1 answer:
Elden [556K]3 years ago
3 0

Answer:

% error Aluminum: 0.34%

% error Steel: 16.67%

% error Lead: 23.08%

Explanation: Given our observed values of specific heat, to find the % error, we must know the true values as well. % error can be defined as, % error = |observed value - true value | / true value.

Our given data to solve this problem is as follows:

Aluminum Specific Heat Observed Value: 0.9 (given), Aluminum Specific Heat True Value: 0.897 (research).

Steel Specific Heat Observed Value: 0.49 (given), Steel Specific Heat True Value: 0.42 (research).

Lead Specific Heat Observed Value: 0.16 (given), Lead Specific Heat True Value: 0.13 (research).

___________

Since we have all the information, just subtract the true value from the observed value, and divide by the true value.

Aluminum Specific Heat % error:

observed value - true value / true value →

0.9 - 0.897 / 0.897 = 0.003 / 0.897 = 1/299 ≈ 0.34 %

Steel Specific Heat % error:

observed value - true value / true value →

0.49 - 0.42 / 0.42 = 0.07 / 0.42 = 1/6 ≈ 16.67%

Lead Specific Heat % error:

observed value - true value / true value →

0.16 - 0.13 / 0.13 = 0.03 / 0.13 = 3/13 ≈ 23.08%

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Answer:

Number of moles = 10.6 mol

Explanation:

Given data:

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)

Number of moles of citric acid = ?

Solution:

Formula:

Number of moles = mass/molar mass

Now we will calculate the molar mass of citric acid:

C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)

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Number of moles = 10.6 mol

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hope this helped

please give brainlist

8 0
3 years ago
Need help !!!!! ASAP
Ksivusya [100]
<h2>Hello!</h2>

The answer is:

We have that there were produced 0.120 moles of CO_{2}

n=0.120mol

<h2>Why?</h2>

We are asked to calculate the number of moles of the given gas, also, we  are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

PV=nRT

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

R=62.363\frac{mmHg.L}{mol.K}

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

We can convert from Celsius degrees to Kelvin using the following formula:

Temperature(K)=Temperature(C\°) + 273K

So, we are given the following information:

Pressure=760mmHg\\Volume=2.965L\\Temperature=25.5C\°=25.5+273K=298.5K

Now, isolating the number of moles, and substituting the given information, we have:

PV=nRT

n=\frac{PV}{RT}

n=\frac{PV}{RT}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole

Hence, we have that there were produced 0.120 moles of CO_{2}

n=0.120mol

Have a nice day!

7 0
3 years ago
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