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3 years ago

Help plz this is part b to my last question

Chemistry

1 answer:

Elden [556K]3 years ago

3 0

Answer:

% error Aluminum: 0.34%

% error Steel: 16.67%

% error Lead: 23.08%

Explanation: Given our observed values of specific heat, to find the % error, we must know the true values as well. % error can be defined as, % error = |observed value - true value | / true value.

Our given data to solve this problem is as follows:

Aluminum Specific Heat Observed Value: 0.9 (given), Aluminum Specific Heat True Value: 0.897 (research).

Steel Specific Heat Observed Value: 0.49 (given), Steel Specific Heat True Value: 0.42 (research).

Lead Specific Heat Observed Value: 0.16 (given), Lead Specific Heat True Value: 0.13 (research).

___________

Since we have all the information, just subtract the true value from the observed value, and divide by the true value.

Aluminum Specific Heat % error:

observed value - true value / true value →

0.9 - 0.897 / 0.897 = 0.003 / 0.897 = 1/299 ≈ 0.34 %

Steel Specific Heat % error:

observed value - true value / true value →

0.49 - 0.42 / 0.42 = 0.07 / 0.42 = 1/6 ≈ 16.67%

Lead Specific Heat % error:

observed value - true value / true value →

0.16 - 0.13 / 0.13 = 0.03 / 0.13 = 3/13 ≈ 23.08%

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Answer:

Boron (B) is the element whose IE matches with our data.

Electronic Configuration of boron: $1s^22s^22p^1$

Explanation:

Ionization Energy (IE):

It is the minimum amount of energy which is required to remove the lose electron. If the electron is closer to the nucleus then greater amount of energy is required to remove the electron.

If we look from left to right in a period, ionization energy increases due stability of valance shell.

From the data given to us:

IE₁ = 801

IE₂ = 2427

IE₃ = 3659

IE₄ = 25,022

IE₅ = 32,822

Boron (B) is the element whose IE matches with our data.

Electronic Configuration of boron: $1s^22s^22p^1$

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3 years ago

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Afina-wow [57]

Answer:

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Explanation:

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Answer:

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Answer:

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3 years ago

Help plz this is part b to my last question​

Help plz this is part b to my last question