C + O2 --> CO2
18g C = 18/12.01 = 1.49 moles (Limiting Reagent)
62.3-14.3 = 48g oxygen that reacted
48g O = 3 moles
Answer:
Mass = 4.6 g
Explanation:
Given data:
Number of molecules of sucrose = 8.1 ×10²¹ molecules
Mass of sucrose = ?
Solution:
First of all we will calculate the number of moles by using Avogadro number.
1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules
1.35 × 10⁻² mol
Mass of sucrose:
Mass = number of moles × molar mass
Molar mass = 342.3 g/mol
Mass = 1.35 × 10⁻² mol ×342.3 g/mol
Mass = 462.1 × 10⁻² g
Mass = 4.6 g
Hey there! Let's get that problem solved!
First: Let's define, "solution."
Solution: <span>a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent).
Next: Ask yourself, "can a solution be taken apart?"
In some cases, yes. It can.
The solution of salt water for example, can be physically separated by evaporation. (place salt-water in a pot on a heated stove, place the cover to the pot on the opening, wait a few minutes, remove the top, and you can (and taste) the water without the salt!) </span><span />
Answer:
C solution
Explanation:
i hope that i got it right im not very good with questions