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3 years ago

Calculate the frequency of radiation with a wavelength of 1.08 x 10^-6 m. simple explanation please

1 answer:

8 0

C = vf
c stands for the speed of waves (which is a constant that is 3 x 10^8)
v stands for the wavelength (which is given)
f stands for frequency (what we are solving for)
3 x 10^8 = (1.08 x 10^-6)f
Divide both sides by the given wavelength
f = 2.78 * 10^14 seconds

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Calculate the ph of a 0.021 m nacn solution. [ka(hcn) = 4.9  10–10]

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Answer is: pH of solution of sodium cyanide is 11.3.
Chemical reaction 1: NaCN(aq) → CN⁻(aq) + Na⁺(aq).
Chemical reaction 2: CN⁻ + H₂O(l) ⇄ HCN(aq) + OH⁻(aq).
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3 years ago

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3 years ago

A buret is filled with 0.1517 M naoh A 25.0 mL portion of an unknown acid and two drops of indicator are added to an Erlenmeyer

antiseptic1488 [7]

Answer:

molarity of acid =0.0132 M

Explanation:

We are considering that the unknown acid is monoprotic. Let the acid is HA.

The reaction between NaOH and acid will be:

$NaOH+HA--->NaA+H_{2}O$

Thus one mole of acid will react with one mole of base.

The moles of base reacted = molarity of NaOH X volume of NaOH

The volume of NaOH used = Final burette reading - Initial reading

Volume of NaOH used = 22.50-0.55= 21.95 mL

Moles of NaOH = 0.1517X21.95=3.33 mmole

The moles of acid reacted = 3.33 mmole

The molarity of acid will be = $\frac{mmole}{volumne(mL)}=\frac{0.33}{25}=0.0132M$

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3 years ago

Calculate the frequency of radiation with a wavelength of 1.08 x 10^-6 m. simple explanation please​

Calculate the frequency of radiation with a wavelength of 1.08 x 10^-6 m. simple explanation please