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galina1969 [7]
3 years ago
12

Reaction A has a high activation energy, whereas reacton B has a low activation energy. Which of the statements about reaction A

and reaction B are true? Reaction B is likely to occur at a faster rate than reaction A. Reaction A is more likely to occur at all than reaction B. Reaction B is more likely to occur at all than reaction A. Reaction A is likely to occur at a faster rate than reaction B.
Chemistry
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

The correct answer is:

Reaction B is more likely to occur at all than reaction A.

Explanation:

The activation energy in chemistry is the smallest amount of energy required to cause chemical or nuclear reaction in the reactants in chemical or nuclear systems. The activation energy is denoted by E_{a}, and it is measured in Joules (J), KiloJoules (KJ) or Kilocalories per mole (Kcal/mol)

The activation energy can be thought of simply as the minimum amount of energy required to overcome a barrier that prevents a reaction from occurring, hence, from our question, if Reaction A has a high activation energy, it means that the barrier to be overcome before a reaction will occur is large, meaning that the reaction system is more stable and the reaction is less likely to occur than Reaction B which has a low activation energy, meaning that just a relatively small amount of energy, when applied to the reaction system, will initiate a reaction, making it more likely to occur than reaction A.

You should also note that catalysts are substances that are capable of reducing the activation energy of a system, but remains unchanged at the end of the system.

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Answer:

202 L

Explanation:

Step 1: Write the balanced equation

C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

270 g × 1 mol/180.16 g = 1.50 mol

Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose

The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol

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The volume of 1 mole of an ideal gas at STP is 22.4 L.

9.00 mol × 22.4 L/mol = 202 L

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