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drek231 [11]
3 years ago
5

The sine of the incident angle is 0.217; the sine of the refracted angle is 0.173. calculate the index of refraction.

Physics
2 answers:
notka56 [123]3 years ago
5 0
This can be solve using snell's law. snell's law equation is :

N1 / N2 = sin a2 / sin a1
where N1 is the index of  refraction of the air which is equal to 1
N2 is the index of refraction of the medium
a2 is the angle of refraction
a1 is the incident angle

subsitute the given values
1 / N2 = 0.173 / 0.217
N2 = 1 ( 0.217 / 0.173)
N2 = 1.25 is the index of refraction
Olenka [21]3 years ago
5 0
The sine of the incident angle is 0.217; the sine of the refracted angle is 0.173. calculate the index of refraction.<span>

n = 1.25

78% sure
</span>
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2) Given v₀= 3m/s, a=0.2m/s², t=10 s. Using equation (ii) to get the final velocity v:v=at+v_0=0.2\frac{m}{s^2} * 10s+3\frac{m}{s}=2\frac{m}{s}+3\frac{m}{s}=5\frac{m}{s}

3) Given v₀=0m/s, t₁=10s, t₂=1s and x₀=0. Looking for factor f = x(t₁)/x(t₂) using equation(i) to calculate x(t₁) and x(t₂):

f=\frac{x(t_1)}{x(t_2)}=\frac{\frac{1}{2}at_1^2 }{\frac{1}{2}at_2^2}=\frac{t_1^2}{t_2^2}=\frac{10^2}{1^2}=\frac{100}{1}

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3 years ago
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alexandr402 [8]
We can use the equation for kinetic energy, K=1/2mv².
Your given variables are already in the correct units, so we can just plug in the variables and solve for v. 

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Therefore, the velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s.
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