A car company wants to ensure its newest model can stop in less than 450 ft when traveling at 60 mph. If we assume constant dece
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The force of frictions is opposed to relative motion.
The acceleration of the crate is approximately <u>2.937 m/s²</u>.
Reason:
The given parameters are;
The mass of the wood, m = 100 kg
The force which can move the wood, F = 588 N
Wood on wood static friction, = 0.5
Wood on wood kinetic friction, = 0.3
Solution;
The force of friction, , acting when the crate is moving is given as
follows;
= m × g ×
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore, we have;
= 100 × 9.81 × 0.3 = 294.3
The force of friction, = 294.3 N
The force with which the crate moves, F = 588 - 294.3 = 293.7
The force with which the crate moves, F = 293.7 N
Force = Mass, m × Acceleration, a
Therefore;
The acceleration of the crate, a ≈ <u>2.937 m/s²</u>.
Learn more about friction here: