Ask question

Ask question

All categories

4 years ago

15

A school's new pump can fill the swimming pool in 2 hours, and the old pump takes 5 hours. What is the time required in hours to

fill the pool if both pumps are used together? (Enter your answer as mixed number.)

1 answer:

Vilka [71]4 years ago

6 0

.41 hours. 2/24 • 5/24 =10/24 then 10/24= .41 hours or 24.6 minutes

You might be interested in

3. Describe how sound signals can be transmitted from a cell phone and received by another cell phone.

BartSMP [9]

Answer:

The sound energy travels through the air into the microphone and makes the diaphragm inside vibrate. The sound energy in your voice makes the air vibrate. Vibrating air carries the sound energy into the phone. The diaphragm in the mouthpiece microphone converts sound energy into electrical energy.

Explanation: Hope this helps! :)

4 0

3 years ago

In a single wire, how much current would be required to generate 1 Tesla magnetic field at a 2 meter distance away from the wire

aev [14]

Answer:

12.56 A.

Explanation:

The magnetic field of a conductor carrying current is give as

H = I/2πr ............................... Equation 1

Where H = Magnetic Field, I = current, r = distance, and π = pie

Making I the subject of the equation,

I = 2πrH............... Equation 2

Given: H = 1 T, r = 2 m.

Constant: π = 3.14

Substitute into equation 2

I = 2×3.14×2×1

I = 12.56 A.

Hence, the magnetic field = 12.56 A.

5 0

4 years ago

43. A rocket sled accelerates at a rate of 49.0m/s2. Its passenger has a mass of 75.0 kg. (a) Calculate the horizontal component

lord [1]

(a) 3675 N

Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:

$F_x = m a_x$

where

$F_x$ is the horizontal component of the force

m is the mass of the passenger

$a_x$ is the horizontal component of the acceleration

Here we have

m = 75.0 kg

$a_x = 49.0 m/s^2$

Substituting,

$F_x=(75.0)(49.0)=3675 N$

(b) 3748 N, 11.3 degrees above horizontal

In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:

$R=mg=(75.0)(9.8)=735 N$

where we used

$g=9.8 m/s^2$ as acceleration of gravity.

So, this is the vertical component of the force exerted by the seat on the passenger:

$F_y = 735 N$

and therefore the magnitude of the net force is

$F=\sqrt{F_x^2+F_y^2}=\sqrt{3675^2+735^2}=3748 N$

And the direction is given by

$\theta = tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{735}{3675})=11.3^{\circ}$

4 0

3 years ago

Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?

ozzi

Answer: The forces acting on both of them will increase in magnitude.

Explanation:

According to Coulomb's law, the electrostatic force between two bodies is proportional to the product of their two charges. If the charge on A is increased this product increases in size (it must have been non-zero to begin with, since there was a force between them at first). Thus, the force between them rises.

6 0

3 years ago

The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If

sattari [20]

Answer:

$v=\sqrt{2gh}\ m/s$

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

So

Work done by all forces = Change in kinetic energy

m g h = 1/2 m v² - 0

v² = 2 g h

$v=\sqrt{2gh}\ m/s$

6 0

4 years ago