The answer is the 4th option because they don't use oxygen, that's what they produce
The exact magnification of the objects is calculated by dividing the cinema. We calculate it by diving the erect image size by the object size. From the given above, we find the exact magnification by dividing 5.0 cm by 1.0 cm. Thus, the answer would be 5.
Answer:
The rate of change of the distance is 14.89.
Explanation:
Given that,
Distance = 145 miles
Speed of car = 42 miles/hr
Distance covered by car = 55 miles
We need to calculate the the rate of change of the distance
According to figure,
Let OA is x, and AB is y.
Now, using Pythagorean theorem

On differentiating




Hence, The rate of change of the distance is 14.89.
Answer:
0.405 seconds
Explanation:
Consider the amount of time it takes the block to fall from 53 m up to 14 m above the ground; then consider the amount of time it takes the block to fall from 53 m up to 2 m above the ground.
First, d = (1/2) gt^2 or t= ( 2 d / g)^1/2
= ( 2 × 39 / 9.8)^1/2 = 2.8212 seconds
Then, to fall from 53 down to 2 meters...
d = (1/2) gt^2 or t= ( 2 d / g)^1/2
= ( 2 * 51/ 9.8 )^1/2 = 3.2262 seconds
So the amount of time it takes for the block to fall from 14 m upto 2 m above the ground
3.2262 - 2.8212 = 0.405 seconds
this is how much time there is from when the man sees the block until it hits him. Not much time...
Answer:
21.42m/S
Explanation:
Hello!
To solve this problem we must perform the following steps.
1. Find the distance traveled from until the driver reacts, this is achieved using the equation for constant speed movement.
X1=VT
where
x= distance traveled
v=initial speed
T=time=0.75s
X1=0.75Vo
we must take into account that the total distance is the sum of the distance at which the pilot reacts (x1) and when it starts to decelerate (x2)
39=0.75Vo+X2
X2=39-0.75Vo
2. Now we use the equation that defines a movement with constant acceleration.

where
Vf = final speed=0m/s
Vo = Initial speed
A = acceleration
=-10m/s2
X2 = displacement
now we use the ecuation of step 1

solving

Now we solve the quadratic equation and find the value of Vo
the solutions are 21.42m/S, -36.41m/S
as the speed must be positive we conclude that the answer is 21.42m/S