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mestny [16]
4 years ago
15

Explain how understanding of atomic emission spectrum led to development of the atomic theory

Chemistry
1 answer:
Anon25 [30]4 years ago
4 0

Max Planck presented a theoretical explanation of the spectrum of radiation emitted by an object that glows when heated. He argued that the walls of a glowing solid could be imagined to contain a series of resonators that oscillated at different frequencies. These resonators gain energy in the form of heat from the walls of the object and lose energy in the form of electromagnetic radiation. The energy of these resonators at any moment is proportional to the frequency with which they oscillate.

To fit the observed spectrum, Planck had to assume that the energy of these oscillators could take on only a limited number of values. In other words, the spectrum of energies for these oscillators was no longer continuous. Because the number of values of the energy of these oscillators is limited, they are theoretically "countable." The energy of the oscillators in this system is therefore said to be quantized. Planck introduced the notion of quantization to explain how light was emitted.

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Can anyone help with properties of non-metals?
Katen [24]
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3 0
3 years ago
A process stream contains 450 mol/s benzene and 375 mol/s toluene. Calculate the mole fraction of benzene in the process stream.
Tema [17]

Answer:

0.5455

Explanation:

The moles of benzene in the process stream in 1 sec = 450 moles

The moles of toluene in the process stream in 1 sec = 375 moles

So, according to definition of mole fraction:

Mole\ fraction\ of\ benzene=\frac {n_{benzene}}{n_{benzene}+n_{toluene}}

Applying values as:

Mole\ fraction\ of\ benzene=\frac {450}{450+375}

<u>Mole fraction of benzene in the process stream = 0.5455</u>

7 0
4 years ago
The bonds in compound MgSO4 can be described as
Sloan [31]

the answer is IONIC

8 0
3 years ago
Suppose that you have a 60.0% solution of NaOH. How many milliliters of water must be added to 30.0 mL of this solution to prepa
defon

Answer:

  • <u>21.4 ml (second choice)</u>

Explanation:

<u>1) Data:</u>

a) C₁ = 60.0% (initial solution)

b) V₁ = 30.0 ml (initial solution)

c) C₂ = 0% (pure water)

d) V₂ = ? (pure water)

e) C₃ = 35.0% (final concentration)

<u>2) Formula:</u>

  • C₁V₁ + C₂V₂ = C₃V₃
  • V₁ + V₂ = V₃ (assuming volume addtivity)

<u>3) Solution:</u>

<u />

a) Substitute values in the first formula:

  • 60.0% × 30 ml + 0 = 35% (30 ml + V₂)

b) Solve the equation (units are supressed just to manipulate the terms)

  • 18 = 10.5 + 0.35V₂

  • 0.35V₂ = 18 - 10.5 = 7.5

  • V₂ = 7.5 / 0.35 = 21.4 ml ← answer    
3 0
4 years ago
A sample of Neon is in a sealed container held under isothermic conditions. The initial pressure and volume are 2.7 atm and 4.5
Marina CMI [18]

Answer:

The final volume in mL is 7.14 mL or 7.1 mL.

Explanation:

1.Use Boyle's Law(P_{1} V_{1}= P_{2} V_{2}). Re-arrange to solve for V_{2}<em> for the final volume.</em>

<em />

<em>2. Plug in values. </em>V_{2} =\frac{(2.7 atm)(4.5 mL)}{(1.7 atm)}  = 7.14 mL

3 0
2 years ago
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