Let x be the volume of fluid removed and the volume of pure antifreeze that is added. The concentration of antifreeze in the fluid is 0.3, the concentration in pure antifreeze is 1 and that in the final solution is 0.4 The volume of the final solution is 10.
(10 - x)(0.3) + x = 10(0.4)
0.3 + 0.7x = 0.4
x = 1/7 quarts
The volume that should be drained is 1/7 quarts
0.326 moles of gas
Explanation:
Knowing the volume of a gas at standard temperature and pressure (STP) we may calculate the number of moles of the gas using the following formula:
number of moles = volume / 22.4 (L /mole)
number of moles of gas = 7.3 (L) / 22.4 (L /mole)
number of moles of gas = 0.326 moles
Learn more about:
molar volume
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Answer:
The first question is option 2
and the second question in option 1
Explanation:
1.96 pounds, i hope this helped.
