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Vinvika [58]
3 years ago
6

Example of the double inclined plane

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
7 0
<span>Conservation of energy. A ball rolls down a ramp, then up another ramp. Even if the ramps are set at different angles, the final height achieved by the ball is (almost) its original height.</span>
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How does plants react with no scratch?
Andreas93 [3]

Answer:

You see, plants need energy to grow and grow and grow. They use energy from sunlight to make a simple sugar, glucose. Whenever the plant needs energy, it can chomp a little glucose off of the starch.

without energy it wont get energy/food so it will eventually die  

Explanation:

3 0
3 years ago
What is T in the equation G = H - TS?
stellarik [79]
I think it’s A good luck on the answer if it’s not but I’m pretty sure it’s A .
4 0
3 years ago
An atom has the following electron configuration . 1s^ 2 2s^ 2 2p^ 6 3s^ 2 3p^ 6 4s^ 2 How many valence electrons does this atom
stepan [7]
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5 0
3 years ago
State boyl"s law and Charle's law​
zubka84 [21]

Answer:

hey mateee

Boyle's law :-  the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.

Boyle's law can also be formularized as P1V1 = P2V2

Charle's law :-  the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

Charle's law can also be formularized as V1/T1 = V2/T2  

6 0
3 years ago
Calculate E o cell for the reaction: AgCl(s) + NO(g) → Ag(s) + Cl-(aq) + NO3-(aq) (in acidic solution) Use the fact that the red
kaheart [24]

Answer:

-0.74

Explanation:

Let's consider the following redox reaction.

AgCl(s) + NO(g) → Ag(s) + Cl⁻(aq) + NO₃⁻(aq)

We can identify the oxidation and reduction half-reactions.

Reduction (cathode): 1 e⁻ + AgCl(s) → Ag(s) + Cl⁻(aq)

Oxidation (anode): 2 H₂O(l) + NO(g) → NO₃⁻(aq) + 4H⁺(aq) + 3 e⁻

The standard cell potential (E°) is equal to the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red,cat - Ered,an = 0.22 V - 0.96 V = -0.74 V

7 0
3 years ago
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