Question

Calculate the volume in liters of a ×7.7310−5/mmolL silver(II) oxide solution that contains 475.μmol of silver(II) oxide AgO . Round your answer to
3 significant digits.

Answer 1

Answer: Thus volume in liters is $6.14\times 10^3L$

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of silver oxide}}{\text{Volume of solution in L}}$     .....(1)

Molarity of silver oxide solution = $7.73\times 10^{-5}mmol/L=7.73\times 10^{-2}\mu mol/L$      $1mmol=1000\mu mol$

Moles of silver oxide = $475\mu mol$      

Volume of solution in L = ?

Putting values in equation 1, we get:

$7.73\times 10^{-2}\mu mol\L=\frac{475\mu mol}{\text{Volume of solution in L}}\\\\\{\text{Volume of solution in L}}=\frac{475\mu mol}{7.73\times 10^{-2}\mu mol\L}=6.14\times 10^3L$

Thus volume in liters is $6.14\times 10^{3}L$