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Chemistry

2 answers:

ArbitrLikvidat [17]2 years ago

7 0

Answer:

Option B

Explanation:

Magnesium is an alkali earth metal and chlorine is a nonmetal. Due to this, and their differences in electronegativity, the elements form an ionic bond. Since magnesium has two valence electrons, it will give them up to two chlorine atoms (which has 7 valence electrons), which needs them to complete its octet. From this, magnesium forms a cation, and will have the ion formula Mg(2+). The two chlorine atoms form anions, and will have the ion formula Cl(1-).

Terms:

Cation: a positively charged ion
Anion: a negatively charge ion.
Electronegativity: the tendency of an atom in a molecule to attract the shared pair of electrons towards itself.

san4es73 [151]2 years ago

4 0

Your answer is the second one hope helps!,

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NaBr + CaF2 → NaF + CaBr2 What coefficients are needed to balance the chemical equation? A) 1,1,1,1 B) 1,2,1,2 C) 1,2,2,1 D) 2,1

elena-s [515]

D.
2NaBr + CaF2 --> 2NaF + CaBr2 gives you:

2Na 2Na
2Br 2F
1Ca 1Ca
2F 2Br

This is balanced.

7 0

3 years ago

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Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to

NARA [144]

Answer:

Any binary molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.

Explanation:

Going down in a group increases the atomic radius and a greater atomic radius implyes greater ionic radius.

When ionization takes place in these compounds they yelds protons (hidrogen ion) and an lewis base (anion). The greater the ionic radius the greater its stability, thus the periodic tendency is increaing the acidity of binary hidrogen compounds when going down a group. On the other hand going up a group decreases acidity, so any molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.