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Mazyrski [523]
3 years ago
14

Can Someone help me answer the question?

Physics
1 answer:
soldi70 [24.7K]3 years ago
8 0

There must be a description of the ball and its environment,
somewhere earlier on the sheet where we can't see it.  We
don't know what the conditions and environment are around
the ball as it moves downward.  So I can only answer in the
most general way, and make up some scenarios.

If the ball is falling from an airplane, then it has to use some
of its energy to push air out of the way, and even then, it loses
some more energy as the air molecules scrape against its side. 
This is all called 'air resistance'.  It's a form of friction, the form that
takes energy away from anything that's moving through air.

If the ball is rolling across the lawn, then it takes some energy
to bend the blades of grass down along its path.  That's why a
ball that's rolling anywhere on Earth always stops, although
Newton's laws of motion say that an object in motion always
keeps moving and doesn't stop.

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Which of the following must be true about the object labeled X in the circuit below?
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You stand on a merry-go-round which is spinning at f = 0:25 revolutions per second. You are R = 200 cm from the center. (a) Find
ivanzaharov [21]

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

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Therefore,

ω = (2π)(0.25 rev/s)

<u>ω = 1.57 rad/s </u>

(b)

The centripetal acceleration can be found as:

ac = v²/R

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v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

<u>ac = 4.92 m/s² </u>

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

<u>μs = 0.5</u>

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I only speak English

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