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3 years ago

Most of the countries in Europe use SI measurments. How could this be a problem if you went on a trip to Europe?

2 answers:

8 0

The answer is because we use different measurements than any other country (assuming you live int he U.S) so you would become easlily confused

faust18 [17]3 years ago

5 0

Not knowing how to convert the type of measurement according to your way of learning from where ever you come from.

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A localized impediment to electron flow in a circuit is a:

hichkok12 [17]

This would be the definition of a resistor. These components inhibit or “resist” the flow of a current.

Hope this helps!

8 0

4 years ago

Read 2 more answers

A spherical raindrop 2.5 mm in diameter falls through a vertical distance of 3900 m. Take the cross-sectional area of a raindrop

Karolina [17]

Answer:

276.62 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

Equation of motion

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 3900+0^2}\\\Rightarrow v=276.62\ m/s$

<u>Neglecting air drag</u> the velocity of the spherical drop would be 276.62 m/s

5 0

4 years ago

A 40.0 turn coil of wire of radius 3.0 cm is placed between the poles of an electromagnet. The field increases from 0 to 0.75 T

nadezda [96]

Answer:

Induced emf, $V=3.76\times 10^{-4}\ V$

Explanation:

We have,

Number of turns in the coil, N = 40

Radius of coil, r = 3 cm = 0.03 m

The field increases from 0 to 0.75 T at a constant rate in a time interval of 225 s.

It is required to find the magnitude of the induced emf in the coil if the field is perpendicular to the plane of the coil. The induced emf is given by :

$\epsilon=\dfrac{d\phi}{dt}$

$\phi=NBA\cos\theta$ , is magnetic flux

$\epsilon=NA\dfrac{dB}{dt}\\\\\epsilon=\dfrac{40\times \pi (0.03)^2\times (0.75-0)}{225}\\\\\epsilon=3.76\times 10^{-4}\ V$

So, the magnitude of induced emf is $3.76\times 10^{-4}\ V$ .

7 0

3 years ago

The sun radiates about 3.6 x 1026 joules of energy each second. How much mass does the lose each second? Show all of your work a

AlekseyPX

E=mc^2

hence m= E/c^2
= (3.6x10^26)/(9×10^16)
= 4x 10^9 kg

8 0

3 years ago

Read 2 more answers

Please answer the following question!

Semmy [17]

Answer:

Explanation:

the momentum will always be 0 when it is at rest because the object isnt moving!

Hope this helped!

6 0

2 years ago