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4 years ago

12

Two closed containers look the same, but one is packed with lead and the other with a few feathers. How could you determine whic

h has more mass if you and the containers were orbiting in a weightless condition in outer space?

1 answer:

andrew-mc [135]4 years ago

5 0

If both containers are pushed with equal force, the one moving faster would have less mass

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Taden has found a table of the atmospheric layers of the Sun. However, he can’t make out the names of the layers in the chart.

zhenek [66]

The sun is a ball of hot gases containing different kinds of elements at different cores. It has a very high temperature that radiates all throughout the Milky Way galaxy. The sun has three main parts; photosphere, chromospheres and corona. The outer core of a star located at the chromospheres contains mostly of hydrogen. Inside the hydrogen is helium then carbon, oxygen, neon, magnesium silicon and the inert gas. The photosphere is scattered by the loose electrons in the corona’s plasma.

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3 years ago

Read 2 more answers

Florida is a peninsula bound by the Atlantic Ocean on the east and the Gulf of Mexico on the west. The sea affects temperatures

Andreyy89

They are usually warmer

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3 years ago

Help me please please help

andrew-mc [135]

Answer:

The answer is C.

Explanation:

If you have ever tried doing so, hair stick to the ballon. Opposites attract as well, so the answer is C.

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4 years ago

How much time does it take for a spinning baseball with an angular speed of 38 rad/s to rotate through 15 degrees

Nadusha1986 [10]

Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

Angular distance in radian;

$\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad$

Time of motion is calculated as;

$time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms$

Therefore, the time of motion of the ball is 6.89 ms.

3 0

3 years ago

I’m gym class you run 22m horizontal then climb a rope vertically for 4.8m. What is the direction angle of your total displaceme

Sliva [168]

The answer is: 12.30 degrees.

To solve this problem you must apply the proccedure shown below:

1. You run 22 meters horizontally and then you climb a rope vertically for 4.8 meters.

2. So. let's call the angle $\alpha$ , therefore, you must find it using $tan^{-1}$ , as following:

$tan^{-1}(\alpha)=\frac{opposite}{adjacent} \\opposite=4.8\\adjacent=22$

3. Substitute values and solve for the angle:

$tan^{-1}(\alpha)=\frac{4.8}{22}\\\alpha=12.30degrees$

5 0

3 years ago