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3 years ago

What does "Position (m)” represent in the graph?

Physics

2 answers:

notka56 [123]3 years ago

6 0

Answer: The correct answer is the dependent variable

Explanation:

A dependent variable is defined a the variable whose value changes with respect to the change in the independent variable. In a graph, it is always written on the y-axis.

An independent variable is defined as the variable which does not changed with respect to any variable. In the graphical representation, it is always written on the x-axis.

A direct relationship is defined as the relationship in which if one variable changes, the other variable also changes. If one increase, the other variable also increases and vice-versa.

In the graph, position 'm' is written on the y-axis and hence, is considered as a dependent variable.

SCORPION-xisa [38]3 years ago

5 0

Position (m)” represent the dependent variable in the graph.

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nirvana33 [79]

Answer:

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2 years ago

A student wearing a frictionless roller skates on a horizontal is pushed by a friend with a constant force of 55N. How far must

umka21 [38]

Answer:

6.58m

Explanation:

The kinetic energy = Workdone on the roller

Workdone = Force * distance

Given

KE = Workdone = 362J

Force = 55N

Required

Distance

Substitute into the formula;

Workdone = Force * distance

362 = 55d

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3 years ago

An airplane during departure has a constant acceleration of 3 m / s².

Rama09 [41]

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

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b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = v - u

3 = v - 20

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

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2 years ago

14. Convert 22 degrees celsius to fahrenheit. Please show your work

forsale [732]

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2 years ago

Read 2 more answers

he membrane that surrounds a certain type of living cell has a surface area of 6.0 x 10-9 m2 and a thickness of 1.6 x 10-8 m. As

k0ka [10]

Answer:

$1.54481175\times 10^{-12}\ C$

Explanation:

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

A = Area = $6\times 10^{-9}\ m^2$

d = Thickness = $1.6\times 10^{-8}\ m$

k = Dielectric constant = 5.4

V = Voltage = 86.2 mV

Charge is given by

$Q=CV\\\Rightarrow Q=k\epsilon\dfrac{A}{d}V\\\Rightarrow Q=5.4\times 8.85\times 10^{-12}\times \dfrac{6\times 10^{-9}}{1.6\times 10^{-8}}\times 86.2\times 10^{-3}\\\Rightarrow Q=1.54481175\times 10^{-12}\ C$

The charge on the outer surface is $1.54481175\times 10^{-12}\ C$

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2 years ago