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Mnenie [13.5K]
4 years ago
6

What does "Position (m)” represent in the graph?

Physics
2 answers:
notka56 [123]4 years ago
6 0

<u>Answer:</u> The correct answer is the dependent variable

<u>Explanation:</u>

A dependent variable is defined a the variable whose value changes with respect to the change in the independent variable. In a graph, it is always written on the y-axis.

An independent variable is defined as the variable which does not changed with respect to any variable. In the graphical representation, it is always written on the x-axis.

A direct relationship is defined as the relationship in which if one variable changes, the other variable also changes. If one increase, the other variable also increases and vice-versa.

In the graph, position 'm' is written on the y-axis and hence, is considered as a dependent variable.

SCORPION-xisa [38]4 years ago
5 0
<span>Position (m)” represent  <u>t</u></span><u>he dependent variable</u> in the graph.
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8 0
3 years ago
A boy kicks a football with an initial velocity of 28.0 m/s at an angle of 30.0o above the horizontal. what is the highest eleva
sladkih [1.3K]
As the boy kicks the football with an angle, due to the effect of the gravitational force, the ball would follow a projectile path which is parabolic in nature. From this idea, we can derive equations pertaining to the maximum height that the ball would reach. At the maximum height of the ball, the velocity of the ball would be equal to zero. From the equations for projectile motion, we would obtain the equation as follows:

Maximum height = v0^2 sin^2 (theta) / 2g 
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7 0
3 years ago
The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of 58.0° above the horizo
Norma-Jean [14]

Answer:

0.528m

Explanation:

a)58.7 cm = 0.587 m

Let g = 9.8m/s2. When the frog jumps from ground to the highest point its kinetic energy is converted to potential energy:

E_p = E_k

mgh = mv^2/2

where m is the frog mass and h is the vertical distance traveled, v is the frog velocity at take-off

v^2 = 2gh = 2*9.8*0.587 = 11.5

v = \sqrt{11.5} = 3.4 m/s

b) Vertical and horizontal components of the velocity are

v_v = vsin(\alpha) = 3.4sin(58^0) = 2.877 m/s

v_h = vcos(\alpha) = 3.4cos(58^0) = 1.8 m/s

The time it takes for the vertical speed to reach 0 (highest point) under gravitational acceleration g = -9.8m/s2 is

\Delta t = \Delta v / g = \frac{0 - 2.877}{-9.8} = 0.293s

This is also the time it takes to travel horizontally, we can multiply this with the horizontal speed to get the horizontal distance it travels

s_h = v_ht = 1.8*0.293 = 0.528 m

3 0
3 years ago
you stretch a spring by a distance of 0.3 m. the spring has a spring constant of 440 n/m. when you release the spring, it snaps
Alina [70]

Answer:

19.8 J

Explanation:

According to the law of conservation of energy, the total mechanical energy of the spring (sum of kinetic energy and elastic potential energy) must be conserved:

K_i + U_i = K_f + U_f (1)

where we have

K_i is the initial kinetic energy of the spring, which is zero because the spring starts from rest (2)

U_i is the elastic potential energy of the spring when it is fully stretched

K_f is the kinetic energy of the spring when it reaches the natural length

U_f is the elastic potential energy of the spring when it reaches its natural length, which is zero because the stretch in this case is zero (3)

So

U_i = \frac{1}{2}k(\Delta x_i)^2

where

k = 440 N/m is the spring constant

\Delta x_i = 0.3 m is the initial stretching of the spring

Substituting,

U_i = \frac{1}{2}(440)(0.3)^2=19.8 J

And so using eq.(1) and keeping in mind (2) and (3) we find

K_f= U_i = 19.8 J

8 0
3 years ago
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