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tankabanditka [31]

3 years ago

9

Over four evenings, Ms. Cross grades 6 papers, 8 papers, 9 papers, and 7 papers. She wants to grade an average of 9 papers a nig

ht. What would be a reasonable estimate of how many papers Ms. Cross must grade on the fifth day to reach that goal? 18 15 11 19

1 answer:

dexar [7]3 years ago

5 0

Is this math for college or Highschool

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Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!

sweet-ann [11.9K]

Answer/Step-by-step explanation:

All of the solutions to the equation 3x^2 - 12 = 0 are x = 12 and x = -2

Answer: False

Explanation:

$3x^2-12+12=0+12$

$3x^2=12$

$\frac{3x^2}{3}=\frac{12}{3}$

$x^2=4$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

$x=2,\:x=-2$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

There are two unique solutions to the equations (x-3)^2 = 16

Note: Each variable in the matrix can have only one possible value, and this is how you know that this matrix has one unique solution.

Answer: True

Explanation:

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=7,\:x=-1$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Ths solutions for the equation 2(x-3)^3 - 18 = 0 are x = 6 and x = 0

Answer: False

Explanation:

$2\left(x-3\right)^3-18+18=0+18$

$2\left(x-3\right)^3=18$

$\frac{2\left(x-3\right)^3}{2}=\frac{18}{2}$

$\left(x-3\right)^3=9$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$=\sqrt[3]{9}+3,\:x=\frac{6-\sqrt[3]{9}}{2}+i\frac{\sqrt[3]{9}\sqrt{3}}{2},\:x=\frac{6-\sqrt[3]{9}}{2}-i\frac{\sqrt[3]{9}\sqrt{3}}{2}$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Answer: False

Explanation:

$2\left(x-5\right)^2-8+8=0+8$

$2\left(x-5\right)^2=8$

$\frac{2\left(x-5\right)^2}{2}=\frac{8}{2}$

$\left(x-5\right)^2=4$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=7,\:x=3$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

Answer: False

Explanation:

$\left(x+3\right)^2-25+25=-8+25$

$\left(x+3\right)^2=17$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{17}-3,\:x=-\sqrt{17}-3$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

Answer: False

Explanation:

$\frac{2\left(2x-1\right)^2}{2}=\frac{18}{2}$

$\left(2x-1\right)^2=9$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=2,x=-1$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The only solution for equation (2x-1)^2-49=0 is x = 4

Answer: False
Explanation:

$\left(2x-1\right)^2-49+49=0+49$

$\left(2x-1\right)^2=49$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=4,\:x=-3$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

Answer: True
Explanation:

$3\left(x+2\right)^2-3+3=0+3$

$3\left(x+2\right)^2=3$

$\frac{3\left(x+2\right)^2}{3}=\frac{3}{3}$

$\left(x+2\right)^2=1$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=-1,\:x=-3$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x = -6

Answer: True

Explanation:

$5x^2-180+180=0+180$

$5x^2=180$

$\frac{5x^2}{5}=\frac{180}{5}$

$x^2=36$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{36},\:x=-\sqrt{36}$

$x=6,\:x=-6$

<u><em>~Lenvy~</em></u>

7 0

2 years ago

Which of the following absolute value functions fits the graph shown above

kirill [66]

I can't answer your question if you dont give me answer choices! I'm sorry i couldn't help!

5 0

3 years ago

What is the product in simplest form? State any restrictions on the variable. Please show your work.

mote1985 [20]

You have the following expressions given in the problem above:

(y^2/y-3)(y^2-y-6/y^2+y)

By applying the exponents properties, you can simplify it, as it shown below:

(y^2/y-3)(y^2-y-6/y^2+y)
(y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
(y^4-y^3-6y^2)/(y^3-2y2-3y)

Then, you have:
y^2(y^2-y-6)/y(y^2-2y-3)
(y^2-y-6)/(y^2-2y-3)

The answer is: (y^2-y-6)/(y^2-2y-3)

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3 years ago

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What is 2412÷12 because i dont now

Salsk061 [2.6K]

Answer:

201

Step-by-step explanation:

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3 years ago

O. Find the value of x 1f 5 - 8x =29<br>(a)-3<br>(b) - 2<br>(d) 2<br>(e) 3<br>(c) o

timama [110]

Answer:

-3 is the answer of this question

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3 years ago

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