Well the basic equation for velocity is v=d/t where d is distance and t is time. So v=2m/50s and the answer is v=0.04meter/second.
Answer:
leather
Explanation:
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To solve this problem, it would be helpful to know the density of 1 block
Density is defined as the mass of the substance per volume.
From the example given,
The density of the block is (7g)/(15.625 units^3) or 0.448 g/units^3.
So, if a block is added, the new mass is 7g + 7g = 14 g
And the volume 14 g /(density) = 1 unit^3
Answer:
k = 
b = 
t = 
Solution:
As per the question:
Mass of the block, m = 1000 kg
Height, h = 10 m
Equilibrium position, x = 0.2 m
Now,
The velocity when the mass falls from a height of 10 m is given by the third eqn of motion:

where
u = initial velocity = 0
g = 10
Thus

Force on the mass is given by:
F = mg = 
Also, we know that the spring force is given by:
F = - kx
Thus

Now, to find the damping constant b, we know that:
F = - bv

Now,
Time required for the platform to get settled to 1 mm or 0.001 m is given by:
