<span>Mass of the ball is m = 0.10kg
Initial speed of the Ball v = 15m/s
a. When the ball is at maximum height the velocity is 0
Momentum of ball = mass x velocity
Momentum = 0.10kg x 0 = 0
b. Getting the maximum height,
Using the conservation of energy equation KEinitial = mgh
1/2mVin^2 = mgh => h = v^2/2g
h = 15^2/2x9.8 = 11.48m => Half Height h = 5.96m
Applying the conservation of energy equation at halfway V^2 = 2gh
V = square root of (2x9.8x5.96) => V = square root of (116.816)
So the velocity at the half way V = 10.81 m/s
Momentum M = m x V => M = 0.10 x 10.81 => M = 1.081kg-m/s</span>
Answer:
Significant Other
Explanation:
that comes to mind when I see that
12 V is the f.e.m.

of the battery. The potential difference that is applied to the motor is actually the fem minus the voltage drop on the internal resistance r:

this is equal to the voltage drop on the resistance of the motor R:

so we can write:

and using

and

we can find the current I:
Answer:
9 volts (assuming 0.60 is in Amperes)
Explanation:
Recall that Ohms law can be expressed as
V = IR, where
V = voltage,
I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)
R = resistance (given as 15 ohm)
substituting the above values into the formula
V = IR
V = (0.6)(15)
V = 9 Volts
I’d say two soccer balls that are touching each other, I hope that helps!