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Alex17521 [72]
3 years ago
12

you apply the same amount of heat to five grams of water and five grams of aluminum the temperature of the aluminum increases mo

re than the temp of the water what can you conculde
Physics
2 answers:
Triss [41]3 years ago
6 0
I can conclude that the aluminum heats up faster then the water, since how they are made up is more different, each has a different compound to it, plus water is more denser<span />
blondinia [14]3 years ago
6 0

Answer:

As we know that heat given to a substance is given by the formula as

Q = m C\Delta T

now we know that

\Delta T = \frac{Q}{m C}

now we know that aluminium and water both are of same mass and both are given same amount of heat so the value of Q and m will be same.

So here we can say that change in temperature depends inversely on the specific heat capacity.

So here if more specific heat capacity then there will be less change in temperature.

so we can conclude that since temperature of aluminium increases more so the specific heat capacity of aluminium will be less than that of water.

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A car maintains a constant speed v as it traverses the hill and valley as shown below. Both the hill and valley have a radius of
Zigmanuir [339]

Answer:

As given that the car maintains a constant speed v as it traverses the hill and valley where both the valley and hill have a radius of curvature R.

(i) At point C, the normal force acting on the car is largest because the centripetal force is up. gravity is down and normal force is up. net force is up so magnitude of normal force must be greater than the car's weight.

(ii) At point A, the normal force acting on the car is smallest because the centripetal force is down. gravity is down and normal force is up. net force is up so magnitude of normal force must be less than car's weight.

(iii) At point C, the driver will feel heaviest because the driver's apparent weight is the normal force on her body.

(iv) At point A, the driver will feel the lightest.

(v)The car can go that much fast without losing contact with the road at A can be determined as follow:

Fn=0 - lose contact with road

Fg= mv²/r

mg=mv²/r

v=sqrt (gr)

8 0
3 years ago
Which represents a deletion of the section of DNA shown here, a-c-t-g-g-a-t?
Harman [31]
I would say that the answer is A.
6 0
3 years ago
A hockey puck is traveling to the left with a velocity of v=10 when it is struck by the hockey stick
Lera25 [3.4K]
We have to calculate the impulse of a hockey puck.
Imp = m * ( v 1 - v 2 ) = m * Δ v
v 1 = - 10 i m/s,
v 2 = ( 20 * cos 40° ) i + ( 20 * sin 40° ) j =
= ( 20 * 0.766 ) i + ( 20 * 0.64278 ) j = ( 15.32 i + 12.855 j ) m/s
Δ v = ( 15.32 i + 12.855 j ) - ( - 10 i ) =
= 15.32 i + 12.855 j + 10 i = 25.32 i + 12.855 j
| Δv | = √ ( 25.32² + 12.855²) = √806.35 = 28.4 m/s
Imp = 0.2 kg * 28.4 m/s = 5.68 N-s
Answer: D ) 5.68 N-s. 
 
4 0
3 years ago
Why is natural gas referred to as a fossil fuel?
Yuri [45]
I believe it would be choice A. but not 100% possitive
7 0
3 years ago
When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amp
Paraphin [41]

Answer:

796.18 Hz

Explanation:

Applying,

Maximum velocity = Amplitude×Angular velocity

Therefore,

V' = A(2πf)............... Equation 1

Where V' = maximum velocity of the eardrum, A = Amplitude of vibration of the eardrum, f = frequency of the eardrum vibration, π = pie

make f the subject of the equation

f = V'/2πA................ Equation 2

From the question,

Given: V' = 3.6×10⁻³ m/s, A' = 7.2×10⁻⁷ m,

Constant: 3.14.

Substitute these values into equation 2

f = 3.6×10⁻³/( 7.2×10⁻⁷×2×3.14)

f = 796.18 Hz

6 0
3 years ago
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