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Anton [14]
3 years ago
15

a load of 45 N attached to a spring that is hanging vertically stretches the spring 0.14 m. What is the spring constant?

Physics
2 answers:
vredina [299]3 years ago
4 0

Answer:

Spring constant, k = 321.42 N/m

Explanation:

Force acting on spring, F = 45 N

Displacement caused due to stretching, x = 0.14 m

Using Hooke's law :

F=-kx

Where

k is the spring constant

k=\dfrac{F}{x}

k=\dfrac{45\ N}{0.14\ m}

k = 321.42 N/m

Hence, this is the required solution.

zhenek [66]3 years ago
3 0
According to Hooke's law, Force = spring constant x displacement of the spring. Spring constant = Force/displacement in spring = 45/0.14 = 321.42 N/m. Hope this helps!
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Answer:

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<u>Vectors in the plane </u>

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D=\sqrt{X_A^2+X_B^2}

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garri49 [273]

Answer:

Explanation:

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castortr0y [4]

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

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The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

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t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

here, t1 is the average time for first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

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here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Learn more about the velocity here:

brainly.com/question/862972

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