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2 years ago

a load of 45 N attached to a spring that is hanging vertically stretches the spring 0.14 m. What is the spring constant?

Physics

2 answers:

vredina [299]2 years ago

4 0

Answer:

Spring constant, k = 321.42 N/m

Explanation:

Force acting on spring, F = 45 N

Displacement caused due to stretching, x = 0.14 m

Using Hooke's law :

$F=-kx$

Where

k is the spring constant

$k=\dfrac{F}{x}$

$k=\dfrac{45\ N}{0.14\ m}$

k = 321.42 N/m

Hence, this is the required solution.

zhenek [66]2 years ago

3 0

According to Hooke's law, Force = spring constant x displacement of the spring. Spring constant = Force/displacement in spring = 45/0.14 = 321.42 N/m. Hope this helps!

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aleksley [76]

Answer:

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Explanation:

The question is incomplete. Here is the complete question.

Three capacitors C1-11.7 μF, C2 21.0 μF, and C3 = 28.8 μF are connected in series. To avoid breakdown of the capacitors, the maximum potential difference to which any of them can be individually charged is 125 V. Determine the maximum energy stored in the series combination.

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Since the capacitors are connected in series.

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2 years ago

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