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Anton [14]
3 years ago
15

a load of 45 N attached to a spring that is hanging vertically stretches the spring 0.14 m. What is the spring constant?

Physics
2 answers:
vredina [299]3 years ago
4 0

Answer:

Spring constant, k = 321.42 N/m

Explanation:

Force acting on spring, F = 45 N

Displacement caused due to stretching, x = 0.14 m

Using Hooke's law :

F=-kx

Where

k is the spring constant

k=\dfrac{F}{x}

k=\dfrac{45\ N}{0.14\ m}

k = 321.42 N/m

Hence, this is the required solution.

zhenek [66]3 years ago
3 0
According to Hooke's law, Force = spring constant x displacement of the spring. Spring constant = Force/displacement in spring = 45/0.14 = 321.42 N/m. Hope this helps!
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You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 11-m-hi
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Answer:

m = maximum mass of the coaster = 410 kg

d = maximum spring compression = 2.3 m

h = maximum height of the track = 11 m

H = maximum difference in height of the track = 19 m

g = acceleration by gravity = 9.8 m/s²

k = spring constant (without safety margin) = ?

K = spring constant (with safety margin) = ?

V = maximum speed of the coaster = ?

The gravitational potential energy of the coaster on the top of the 11 m high hill (relative to its initial starting point) is:

PEg = m g h

PEg = (410 kg) (9.8 m/s²) (11 m)

PEg = 44198 J

To reach that height, the elastic potential energy stored in the spring must be the same, so:

PEg = PEe = k d² / 2

(44198 J) = k (2.3 m)² / 2

k = 16710 N/m

Adding 14% to that value, you get:

K = 1.14 (16710 N/m)

K = 19045 N/m - answer spring constant

When fully compressed, the elastic potential energy stored in the spring is:

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The difference in height between the starting point and the lowest point of the track is:

Δh = H - h

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Δh = 8 m

So the initial gravitational potential energy of 330 kg coaster, relative to the lowest point, is

PEg = m g Δh

PEg = (340 kg) (9.8 m/s) (8 m)

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The total energy of the coaster at its starting point (again, relative to the lowest point) is:

TE = PEe + PEg

TE = (51326J) + (26656 J)

TE = 77982J

At the lowest point of the track, all that energy is converted to kinetic energy, so the speed at that point will be:

TE = KE = m V² / 2

(77982 J) = (340kg) V² / 2

V = 21.46 m/s - answer maximum speed

4 0
3 years ago
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