In this case, we are going to assume that there are 100 atoms to make things easier.
Let R% be the abundance of n-15. With this in mind, we calculate the abundance of n-14 to be 100%-R%
14.0031*(100-R)% + 15.001 * R%= 14.00674
In this case, we can delete or ignore the % sign since we do not want to carry it around, however, we need to keep in mind that the final answer is in %
14.0031*(100-R) + 15.001 * R= 14.00674
1400.31-14.0031R+15.001R=1400.674
0.9979R=0.364
R=0.3648
Then, the abundance of n-15 is 0.3648%
Answer: base times height
Explanation:
It's the form of energy in a moving object or a particle. It is present in any object that has a mass and a speed.
Kinetic energy = 1/2 mv²
Answer:
The density of the metal is 3.457 g/cm³.
Explanation:
Given,
mass of metal = 121 grams
Volume = 35 cm³.
Density = ?
Density of the metal can be found by using the formula
Density = Mass/Volume
Substituting the values,
Density = 121/35 = 3.457 g/cm³.
