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ladessa [460]
3 years ago
8

12. Compare and contrast hydrogen bonds and van der Waals interactions.

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
4 0

Explanation:

Van der Waals interactions occur between any two or more molecules. They are caused by a fluctuation in electron density, as electrons are not actually fixed in a shell, but actually freely moving as a 'cloud of electron density'. This means that sometimes one end of a molecule can become more partially negatively charged as all electrons move to that side, and conversely it can attract the more partially positive end of a molecule (that has little electrons).

Hydrogen bonds only occur between molecules that contain oxygen, nitrogen and fluorine bonded to a hydrogen atom.

Hydrogen bonding is also the strongest intermolecular force there is, but not strong in comparison to ionic and covalent bonds. Therefore, hydrogen bonds are much stronger than Van der Waals forces. Hydrogen bonds only form if oxygen, nitrogen and fluorine are bonded to a hydrogen atom, as they have the greatest electronegativity differences (look at an electronegativity table), and when the overall molecule is polar (have unequal charges). This allows the molecule to be able to attract another molecule from one of the bonded atoms to a hydrogen atom.

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Explanation:

A gas has a temperature of 273.15 K and a pressure of 101.325 kPa. It can be concluded that this gas has reached standard temperature and pressure.

Standard temperature is zero degree celcius which corresponds to 273.15 degree kelvin.

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Phosphorus react with carbon<br>​
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2Al + 6HCl → 2AlCl3 + 3H2 If the chemical reaction produces 129 grams of AlCl3, how many grams of H2 are also produced?
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So,

Our conceptual plan is as follows:

g AlCl3 --> mol AlCl3 --> mol H2 --> g H2

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Hope this helps!

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Penicillinase, also known as β‑lactamase, is a bacterial enzyme that hydrolyzes and inactivates the antibiotic penicillin. Penic
sergeinik [125]

Explanation:

The given data is as follows.

        V_{max} = 6.8 \times 10^{-10} \mu mol/min

          K_{m} = 5.2 \times 10^{-6} M

Now, according to Michaelis-Menten kinetics,

              V_{o} = V_{max} \times [\frac{S}{(S + Km)}]

where, S = substrate concentration = 10.4 \times 10^{-6} M

Now, putting the given values into the above formula as follows.

        V_{o} = V_{max} \times [\frac{S}{(S + Km)}]

        V_{o} = 6.8 \times 10^{-10} \mu mol/min \times [\frac{10.4 \times 10^{-6} M}{(10.4 \times 10^{-6}M + 5.2 \times 10^{-6} M)}]

            V_{o} = 6.8 \times 10^{-10} \mu mol/min \times 0.667

                              = 4.5 \times 10^{-10} \mu mol/min

This means that V_{o} would approache V_{max}.

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