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ladessa [460]
3 years ago
8

12. Compare and contrast hydrogen bonds and van der Waals interactions.

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
4 0

Explanation:

Van der Waals interactions occur between any two or more molecules. They are caused by a fluctuation in electron density, as electrons are not actually fixed in a shell, but actually freely moving as a 'cloud of electron density'. This means that sometimes one end of a molecule can become more partially negatively charged as all electrons move to that side, and conversely it can attract the more partially positive end of a molecule (that has little electrons).

Hydrogen bonds only occur between molecules that contain oxygen, nitrogen and fluorine bonded to a hydrogen atom.

Hydrogen bonding is also the strongest intermolecular force there is, but not strong in comparison to ionic and covalent bonds. Therefore, hydrogen bonds are much stronger than Van der Waals forces. Hydrogen bonds only form if oxygen, nitrogen and fluorine are bonded to a hydrogen atom, as they have the greatest electronegativity differences (look at an electronegativity table), and when the overall molecule is polar (have unequal charges). This allows the molecule to be able to attract another molecule from one of the bonded atoms to a hydrogen atom.

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If there is 25.0 L of gas at a temperature of 350C what is the temperature if the volume increases to 75.0L?
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Answer:

The new temperature is 1596 C.

Explanation:

Charles's Law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Statistically, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Being an initial state 1 and a final state 2, it is fulfilled:

\frac{V1}{T1}=\frac{V2}{T2}

In this case:

  • V1= 25 L
  • T1= 350 C= 623 K (being 0 C= 273 K)
  • V2= 75 L
  • T2= ?

Replacing:

\frac{25 L}{623 K} =\frac{75 L}{T2}

Solving:

T2*\frac{25 L}{623 K} =75 L

T2=75 L*\frac{623 K}{25 L}

T2= 1869 K= 1596 C

<u><em>The new temperature is 1596 C.</em></u>

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