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4 years ago

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Sea anemones are predatory invertebrates with stinging tentacles that can paralyze many sea animals. The clownfish is immune to

the sting of the sea anemone and actually lives among its tentacles. The relationship is mutually beneficial—the clownfish often lures meat-eating animals over to the anemone, and the anemone benefits from the meal. The clownfish often gets to eat leftovers from the anemone’s meal?
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1 answer:

N76 [4]4 years ago

6 0

A clownfish will feed on the leftovers of a fish on the anemone in which it lives.

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A well-insulated bucket of negligible heat capacity contains 129 g of ice at 0°C.

Luba_88 [7]

Answer:

The final equilibrium temperature of the system is $T = 12.48^oC$

For the ice it would melt completely the mass that would remain is Zero

Explanation:

In the following question we are provided with

Mass of the ice $M_{i}$ = 129 g = 0.129 kg

Mass of the steam $M_s$ = 19 g = 0.019 kg

Initial temperature is $T_i$ = 0°C

Temperature of steam $T_s$ = 100°C

Following the change of state of water in the question

The energy required by ice to change to water is mathematically given as

$Q_A = M_iL_f$

Where $L_f$ is a constant known as heat of fusion and the value is $334*10^3 J/kg$

$Q_A = 0.129 *334 *10^3 = 43086 J$

The energy been released when the steam changes to water is mathematically given as

$Q_B = M_s * L_v$

Where $L_v$ is a constant known as heat of vaporization and the value is $2256*10^3J/kg$

$Q_B = 0.019 * 2256*10^3 = 42864J$

The energy released when the temperature of water decrease from 100°C to 0°C is

$Q_C = M_s *C_water ($ 100°C)

Where $C_{water}$ is the specific heat of water which has a value $4186J/kg \cdot K$

$Q_C = 0.019 *4186*100 = 7953.4$

Looking at the values we obtained we noticed that ]

$Q_B + Q_C > Q_A$

What this means is that the ice will melt

bearing in mind the conservation of energy

looking the way at which water at different temperature were mixed according to the question

Heat lossed by the vapor = heat gained by ice

$Q_B + M_s *C_{water}(100-T) = Q_A + M_i C_{water} T$

$T = \frac{Q_B+M_s *C_{water}(100^oC)-Q_A}{(M_s *C_{water})+(M_i*C_{water})}$

$T = \frac{42864+7953.4-43086}{(0.019+0.129)(4186)}$

$T = 12.48^oC$

3 0

4 years ago

Two vectors, r and c, are equal: r = c. Which of the following statements are true? (Select all that apply.)

s344n2d4d5 [400]

Answer:

(A) The y-component of r must be equal to the y-component of c

(B) The x-component of r must be equal to the x-component of c

(C) The z-component of r must be equal to the z-component of c

(F) The unit vector r must be equal to the unit vector c.

Explanation:

If two vectors are equal there are some conditions must be satisfy for the two vectors to be equal.

Let us suppose 2 vectors as,

$A=a_{1}i+ a_{2}j+a_{3}k$ and

$B=b_{1}i+ b_{2}j+b_{3}k$

The conditions for the above two vectors should be equal are:

(1) $a_{1}=b_{1}$ , $a_{2}=b_{2}$ , and $a_{3}=b_{3}$ .

(2) Unit vector of A must be equal to unit vector of B.

(3) Magnitude of both the vectors should be equal.

Now, according to question and observing above conditions of equality for r and c to be equal, the statements should be true are:

(A) The y-component of r should be equal to the y-component of c

(B) The x-component of r should be equal to the x-component of c

(C) The z-component of r should be equal to the z-component of c

(F) The unit vector r should be equal to the unit vector c.

6 0

3 years ago

A father uses a rope to pull a child on a sled at a constant speed. of the ones listed which forces are present?

Amanda [17]

All the forces may be present.

The child on the sled has a weight- which is due to the force of gravity on the child and the sled.

The sled and the child exert a force on the ground equal to the combined weight of the sled and the child. The ground exerts a normal force on the sled.

The force used by the father to pull the sled is the applied force.

The sled slides on the ground and as a result, the force of friction exists between the ground and the sled, directed opposite to the direction of the motion of the sled.

The father pulls the sled using a rope. As a result, the rope is under Tension.

As the sled moves it also experiences a force of air resistance, which is dependent on the sled's speed.

However, since the father pulls the sled along with constant speed, the sum of all the forces acting on the sled is zero.

Since there is no movement in the upward or downward directions, the weight of the child and the sled is equal to the normal force acted upon the sled by the ground.

The force applied by the father on the rope is equal to the tension in the rope.

Friction and air resistance act opposite to the direction of motion of the sled. for the sled to move at constant speed, the tension in the rope must be equal to the sum of the forces due to friction and air resistance.

4 0

3 years ago

How do the linear equation and quadratic equation are differ? What do we suffer on earth? What if we would live on the moon /sun

Aleksandr [31]

A quadratic equation is a parabola and a linear equation is a straight line.

Quadratic Equation is an equation in which the power of variable mostly x is two.

Standard quadratic equation is $ax^{2} +bx+c=0$

Any linear equation have form like $y=mx+c$

The moon has no atmosphere, no weather and no oceans of water. Its surface is in a perpetual vacuum.

Because the moon's gravity is only one-sixth that of the Earth's gravity, Apollo astronauts had to risk of stumbling or falling.

Astronauts on the moon were protected from the extreme temperatures by their spacesuits. The suits had several layers of insulating material covered by a highly reflective outer layer.

Learn more:

brainly.com/question/9201543

4 0

2 years ago

Read 2 more answers

. A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is

zysi [14]

V^2 = u^2 + 2gr, where v - speed, u - initial speed=0, r - displacement (or height)
v^2 = 0 + 2*10*5.4
v = 10.2 m/s

4 0

3 years ago

Read 2 more answers