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liubo4ka [24]
3 years ago
10

What power does he develop?

Physics
1 answer:
Andrews [41]3 years ago
7 0
Power generates when a sudden force is applied.
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rosijanka [135]

Answer: abdominal muscles.

Explanation:

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A measure of how easily current will pass through a material ?
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It is Conductivity because it is the measure of the ease.

6 0
3 years ago
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s^2. The acce
jeka94

Answer:

The maximum height will be 7408.8 meters

Explanation:

final velocity = initial velocity + acceleration × time  

final velocity = 0 m/s + 58.8 m/s^2 ×6 s  

Final velocity = 352.8 m/s  

final velocity ^2 = initial velocity ^2 + 2 × acceleration × displacement  

(352.8)^2 = (0)^2 + 2×58.8 ×displacement  

Solving for displacement,

height = 1058.4 meters.  

After this, the rocket is in free fall, we can use the same equation.  

final velocity ^2 = initial velocity ^2 + 2 ×acceleration×displacement  

final velocity = 0  

0^2 = 352.8^2 + 2×(-9.8)×displacement  

displacement = 6350.4 meters  

the maximum height will be 7408.8 meters

3 0
4 years ago
A flock of geese is flying south for the winter. In order to maintain a “V” shape, each goose is flying at the same constant vel
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B the goose with most mass
this is because momentum=mass x acceleration
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3 0
3 years ago
Suppose the charges attracting each other in the above situation have an equal magnitude. Find the charge.
LiRa [457]

The force between the two point charge when they are separated by 18 cm is 3 N

<h3>How do I determine the force when they are 18 cm apart?</h3>

Coulomb's law states as follow:

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Kq₁q₂ => constant

F₁r₁² = F₂r₂²

Where

  • F₁ and F₂ are the initial and new force
  • r₁ and r₂ are the initial and new distance apart

With the above formula, we can obtain the force between the two point charge when they are 18 cm apart. Details below:

  • Initial distance apart (r₁) = 6 cm
  • Initial force of attraction (F₁) = 27 N
  • New distance apart (r₂) = 18 cm
  • New force of attraction (F₂) =?

F₁r₁² = F₂r₂²

27 × 6² = F₂ × 18²

972 = F₂ × 324

Divide both side by 324

F₂ = 927 / 324

F₂ = 3 N

Thus, the force when they are 18 cm apart is 3 N

Learn more about force:

brainly.com/question/28569085

#SPJ1

7 0
2 years ago
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